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Sav [38]
4 years ago
12

How many moles are in 2.3 grams of phosphorus

Chemistry
1 answer:
dmitriy555 [2]4 years ago
8 0
Molar mass of  phosphorus (p) : 30.9 g/mol

1 mole P ----------- 30.9 g
x mole -------------- 2.3 g

30.9 * x = 2.3* 1

30.9 x = 2.3

x = 2.3 / 30.9

x = 0.07 moles

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Read 2 more answers
An iron nail rusts when exposed to oxygen. According to the following reaction, how many grams of iron(III) oxide will be formed
-Dominant- [34]

Answer:

53.2

Explanation:

The balanced reaction is:

2Fe(s) + 3O₂(g) → Fe₂O₃

It means that 3 moles of oxygen form 1 mol of iron(III) oxide. The molar masses are: Fe = 55.8 g/mol and O = 16 g/mol. So

O₂ = 2x 16 = 32 g/mol

Fe₂O₃ = 2x55.8 + 3x16 = 159.6 g/mol

So, 32 g of O₂ corresponds to 1 mol of O₂. The stoichiometry calculus must be (always in moles):

3 mol of O₂ ------------------------ 1 mol of Fe₂O₃

1 mol of O₂  ------------------------ x

By a direct simple three rule:

3x = 1

x = 1/3 mol of Fe₂O₃

The mass is the molar mass multiplied by the number of moles, so:

m = 159.6x (1/3)

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6 0
3 years ago
What is a substanceeas​
Mumz [18]

Answer:

substance*? a particular kind of matter with uniform properties.

Explanation:

5 0
3 years ago
If 420 joules of heat energy is added to 25 grams of water at 25 degrees celcius, what will be the final temperature of the wate
natka813 [3]

Answer:

T2 = 29°C

Explanation:

Given data:

Heat added = 420 j

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Initial temperature = 25°C

Final temperature = ?

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It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water = 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values.

420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)

420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)

420 j = 104.5  j/°C × (T2 - 25°C)

420 j /104.5  j/°C = T2 - 25°C

4°C + 25°C = T2

T2 = 29°C

4 0
3 years ago
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