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Sav [38]
4 years ago
12

How many moles are in 2.3 grams of phosphorus

Chemistry
1 answer:
dmitriy555 [2]4 years ago
8 0
Molar mass of  phosphorus (p) : 30.9 g/mol

1 mole P ----------- 30.9 g
x mole -------------- 2.3 g

30.9 * x = 2.3* 1

30.9 x = 2.3

x = 2.3 / 30.9

x = 0.07 moles

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Mandelic Acid is an organic acid composed of carbon (63.15%), hydrogen (5.30%), and oxygen (31.55%). Its molar mass is 152.14 g/
Dafna1 [17]

Answer:

Empirical formula is C3H3O

Molecular formula C9H9O3

Explanation:

From the question given, we obtained the following data:

Carbon = 63.15%

Hydrogen = 5.30%

Oxygen = 31.55%

We can obtain the empirical and molecular formula by doing the following as illustrated in the attached file. Please see attachment for explanation.

3 0
3 years ago
Read 2 more answers
What is the molar concentration of 35 mL of H2SO4 that neutralizes 25 mL of 0.320M NaOH
stira [4]
V ( H2SO4) = 35 mL / 1000 => 0.035 L

M ( H2SO4) = ?

V ( NaOH ) = 25 mL / 1000 => 0.025 L 

M ( NaOH ) = 0.320 M

number of moles NaOH:

n = M x V

n = 0.025 x 0.320 => 0.008 moles of NaOH

Mole ratio:

<span>2 NaOH + H2SO4 = Na2SO4 + 2 H2O
</span>
2 moles NaOH ---------------------- 1 mole H2SO4
0.008 moles moles NaOH ---------- ??

0.008 x 1 / 2 => 0.004 moles of H2SO4 :

Therefore:

M ( H2SO4) = n / V

M = 0.004 /  0.035

= 0.114 M

hope this helps!



6 0
4 years ago
Science does not include<br><br> beliefs or opinions<br> theories<br> laws<br> conclusions
denpristay [2]
Beliefs or opinions
8 0
4 years ago
The balanced chemical equation for the combustion of butane is: 2C2H2 + 5O2 CO2 + 2H2O 2CH4 + 5O2 2CO2 + 4H2O 2C4H10 + 13O2 8CO2
SCORPION-xisa [38]
Butane is C₄H₁₀.

C_4H_{10} + O_2 \to CO_2 + H_2O \\ \\&#10;\hbox{balance carbon and hydrogen on the right-hand side:} \\&#10;C_4 H_{10} + O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\&#10;\hbox{balance oxygen on the left-hand side:} \\&#10;C_4 H_{10} + \frac{13}{2} \ O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\&#10;\hbox{multiply by 2 to get rid of the fraction:} \\&#10;2 \ C_4H_{10} + 13 \ O_2 \to 8 \ CO_2 + 10 \ H_2O

The balanced equation is 2 C₄H₁₀ + 13 O₂ <span>→</span> 8 CO₂ + 10 H₂O.
3 0
3 years ago
Calculate the energy(J) change associated with an electron transition from n=2 to n=5 in a Bohr hydrogen atom. Put answer in sci
Oliga [24]
The energy at n level of hydrogen atom energy level =13.6/n^2

substiture the respective n values in the equation above and find the difference in the energy levels

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3 0
3 years ago
Read 2 more answers
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