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Sav [38]
4 years ago
12

How many moles are in 2.3 grams of phosphorus

Chemistry
1 answer:
dmitriy555 [2]4 years ago
8 0
Molar mass of  phosphorus (p) : 30.9 g/mol

1 mole P ----------- 30.9 g
x mole -------------- 2.3 g

30.9 * x = 2.3* 1

30.9 x = 2.3

x = 2.3 / 30.9

x = 0.07 moles

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Heat that flows by conduction is the transfer of thermal energy between substances in contact. What must occur for this
Lady bird [3.3K]

Heat flow by conduction requires that the two systems must not be touching each another.

<h3>What is heat energy?</h3>

Heat energy is a form of energy that exists due to a temperature difference between two objects.

Heat energy flows from an object at higher temperature to an object at a lower temperature.

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3 years ago
Determine the total pressure of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, , molar mass = 227.10 g/mol) reacts a
bija089 [108]

Answer:

Total pressure is 1189 atm

Explanation:

This is the reaction:

4C₃H₅(NO₃)₃  →  6N₂  +  O₂  +  12CO₂  +  10H₂O

As we have the volume of TNT, we must know the density to find out the mass and then, apply molar mass to calculate mole.

TNT density = 1.654 g/mL

Density = mass / volume

1.654 g/mL = TNT mass / 50mL

1.654 g/mL . 50mL = TNT mass → 82.7 g

Mass / Molar mass = Mol → 82.7 g / 227.1 g/m = 0.364 mole

Now, we can calculate all the mole for the formed gases.

4 mole of TNT produce 6 mole N₂ ___ 1 mol O₂ __ 12 mole dioxide __ 10 mole of water

0.364 mole of TNT will produce:

- (0.364  . 6) /4 = 0.546 mole of produced nitrogen

- (0.364 . 1) /4 =  0.091 mole of produced oxygen

- (0.364 . 12) /4 = 1.092 mole of produced dioxide

- (0.364 . 10) /4 = 0.91 mole of produced vapour of water.

Total mole = 0.564 + 0.091 + 1.092 + 0.91 = 2.657 mole

Let's apply the Ideal Gases Law to find the total pressure, at STP

In STP, pressure is 1 atm for 1 mole at 273K, in a volume of 22.4 mL

But we have a volume of 50mL, and we have 2.657 total mole

Don't forget to convert 50 mL to L, cause the units for R

50 mL = 0.050L

P . 0.050L = 2.657 mol . 0.082L.atm/mol.K . 273K

P = (2.657 mol . 0.082L.atm/mol.K . 273K) / 0.050L

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Explanation:

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