Answer:
2x^2(3x^2-2x-1)
Step-by-step explanation:
12x^4 - 8x^3 - 4x^2
everything is a multiple of 4 so divide the whole thing by 4
12x^4 - 8x^3 - 4x^2/4= 3x^4-2x^3-1x^2
write it in disturbed form
2(3x^4-2x^3-1x^2)
now if u see we can see that the X will be same, so we also have to factor it out and 2 is the exponent that all can give
2x^2(3x^2-2x-1)
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Answer:
hoskina g to the people ina this contry
We model the ticket as a rectangle.
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer: the dimensions of the ticket are: (10 cm) * (6 cm) Note: see attached image for system solution
Take 12 and divide it by 3 to get the number of slices per quarter. Then multiply the answer you got by four. The answer is 16.