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3 years ago

PLEASE SOMEONE HELP ME I DONT GET IT!!!

Mathematics

2 answers:

Mkey [24]3 years ago

4 0

Answer: b is the answer

Step-by-step explanation:

Alisiya [41]3 years ago

4 0

Answer:

Step One: We need to find a way to equate either the x terms of the y terms in each equation. ...

Step Two: Take equation b) from equation a) to eliminate the x component. ...

Step Three: substitute the value of y into either equation to find the value of x.

Step-by-step explanation:

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What is the domain of the relation y = arccscx?

Stella [2.4K]

Answer:

$y=arc\csc x$

Step-by-step explanation:

The given function is $y=arc\csc x$ .

The domain refers to all values of x for which this function is defined.

Recall that: the domain of $y=arc \sin (x)$ is $-1\le x\le1$

And we know $y=arc\csc x$ is the reciprocal of $y=arc \sin (x)$ .

Therefore the complement of the domain of $y=arc \sin (x)$ which is $(-\infty,-1]\cup [1,+\infty)$ is the domain of $y=arc\csc x$

5 0

2 years ago

A television newscaster from a 24-hour news station wants to estimate the number of hours per day its viewers watch

topjm [15]

Answer:

This isn't the best worded question but from what I understand a larger sample size decreases the margin of error. If he would like a more accurate answer a larger sample size of the viewers will give more accurate answers.

Step-by-step explanation:

4 0

2 years ago

What does 24 ÷ 7 actually mean? Please help as fast as you can!!! :(

Blizzard [7]

Step-by-step explanation:

are you talking about like 24/7 ? or you mean like divide 24÷7 ?

6 0

2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

on a certain hot Summer's Day 613 people use the public swimming pool the daily prices are $1.75 for children $2.25 for adults t

Elodia [21]

389 children and 224 adults were at the pool that day.

Step-by-step explanation:

Cost of one child ticket = $1.75

Cost of one adult ticket = $2.25

Total people = 613

Total receipts worth = $1184.75

Let,

Number of children = x

Number of adults = y

According to given statement;

x+y=613 Eqn 1

1.75x+2.25y=1184.75 Eqn 2

Multiplying Eqn 1 by 1.75

$1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00$

Dividing both sides by 0.50

$\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224$

Putting y=224 in Eqn 1

$x+224=613\\x=613-224\\x=389\\$

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

6 0

3 years ago