V = 1¹/₃πr³
V = 1¹/₃(3.14)(2)³
V = 1¹/₃(3.14)(8)
V = 1¹/₃(25.12)
V ≈ 33.493 in³
Function a is linear, the equation is y = 5/3x or y=5/3x+0
The required equation of a line is y = 9/5 (4x - 12)
Given-
The point from which the line passes through is (3,2)
The slope of the given line m is -4/5.
Equation of the line
The linear equation of a line can be represented by a set of points on a graph using the equation of the line.
The standard form of the line passing through the point x₁, y₁
The slope m is given by,
m = (y - y₁) / (x - x₁)
Put the values of points and slope in the above equation, we get,
-4/5 = (y - 2) / (x - 3)
-4/5(x - 3) = y -2
-4x/5 + 12/5 = y - 2
-1/5 (4x - 12) + 2 = y
y = 9/5 (4x - 12)
The linear equation of a line can be represented by a set of points on a graph using the equation of the line. The following equation depicts a line that crosses (3, 2) and has a slope of -4/5: y = 9/5 (4x - 12)
Learn more about equation of line here;
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Answer:Green
Step-by-step explanation:
Answer:
x = - 9, y = -1
Step-by-step explanation:
<em>Given:</em>
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Solve:
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