Answer:
x=-3
y=2
Step-by-step explanation:
To solve this problem you can use the elimination method:
- Multiply the second equation by -6:
![(-6)5x+y=-13\\-30x-6y=78](https://tex.z-dn.net/?f=%28-6%295x%2By%3D-13%5C%5C-30x-6y%3D78)
- Add both equations:
![6x+6y=-6\\-30x-6y=78\\-------\\-24x=72\\x=-3](https://tex.z-dn.net/?f=6x%2B6y%3D-6%5C%5C-30x-6y%3D78%5C%5C-------%5C%5C-24x%3D72%5C%5Cx%3D-3)
- Substitute the value of x into one of the original equations and solve for y:
![6(-3)+6y=-6\\-18+6y=-6\\6y=12\\y=2](https://tex.z-dn.net/?f=6%28-3%29%2B6y%3D-6%5C%5C-18%2B6y%3D-6%5C%5C6y%3D12%5C%5Cy%3D2)
<u>x-intercepts are found by setting y=0</u>
![y=2x^2-8x-10\rightarrow0=2x^2-8x-10](https://tex.z-dn.net/?f=y%3D2x%5E2-8x-10%5Crightarrow0%3D2x%5E2-8x-10)
<em>factor out a 2</em>
![0=2(x^2-4x-5)\rightarrow0=x^2-4x-5](https://tex.z-dn.net/?f=0%3D2%28x%5E2-4x-5%29%5Crightarrow0%3Dx%5E2-4x-5)
<em />
![0=(x-5)(x+1)](https://tex.z-dn.net/?f=0%3D%28x-5%29%28x%2B1%29)
<em>roots should be </em>x=-1,5
therefore,
x-intercepts are (-1,0) and (5,0)
<u>
</u><u>y-intercepts are found by setting x=0</u>
![y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10](https://tex.z-dn.net/?f=y%3D2x%5E2-8x-10%5Crightarrow%20y%3D2%280%29%5E2-8%280%29-10)
![\rightarrow y=0-0-10=-10](https://tex.z-dn.net/?f=%5Crightarrow%20y%3D0-0-10%3D-10)
therefore,
y-intercept is (0,-10)
Answer:
Step-by-step explanation:
Simplify 3 ratical- 1000
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