Answer:
A. median and mode
B. Mean
C. Mean
d. Positively skewed
Step-by-step explanation:
a. Mean = sum of all values / numbers of values = 1804 / 23 = 78.4. this eliminates the mean and leaves the median and mode, both of which are 62.
Median = middlemost value = 62
Mode = most frequent value = 62
b. Only the Mean would be affected. It would move from 78.4 to 80.6. (calculated as 1853 / 23). The median and mode would not be affected as the 62 would remain the middlemost value and the most frequent.
c. Removing the largest value would result in the mean changing. The mean would now be 73 (calculated as 1607 / 22). Since the values are no longer 23, but now 22, the median would be the average of the 2 middlemost values, ((62+62) / 2) which would still result in 62 as the median.
d. we use the Five number summary:
Median / Interquartile Range = 62
First Quartile / Q1 = (51 +57) / 2 = 54
Third Quartile / Q3 = (99 + 104) / 2 = 101.5
Minimum = 2
Maximum = 197 ; therefore Range = (197 - 2) = 195.
Please see attached box and whisker plot. The distribution is positively skewed.
Rotating 180 degrees about the point p.
If they are perpendicular reflecting across each one will have the same effect as if the point was rotated 180 degrees about the certain point.
5.55% = 1/18
So, cut the cake into 18 equal squares.
The cake is twice as long as it is wide, so that means cut half the cake (6 3/4 x 6 3/4) into 9 pieces, each with a side of 1/3 * 6 3/4 = 2 1/4 inches.
T to the 4th power then multiply by 3.
First find out how much the 4 volleyball nets are by using 4*28 which would equal to 112. Now subtract 112 from 250 and that leaves you with 138. Then you divide 138 by 7 which will give you about 19.7 which you need to take all decimals out since it isn’t an whole number. The gym teacher can only buy 19 volleyballs.