The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.
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How do we calculate the amount invested?</h3>
Let x represents the amount invested in the first account.
Therefore, we have:
Amount invested in the second account = x - 500
Interest income from first account = 3% * x = 0.03x
Interest income from second account = 5% * (x - 500) = 0.05x - 25
Total interest income = 0.03x + 0.05x - 25 = 719
Solving for x, we have:
0.08x = 719 + 25
x = 744 / 0.08
x = $9,300
Substituting for x, we have:
Amount invested in the second account = $9,300 - $500 = $8,800
Learn more about the amount invested here: brainly.com/question/24132106.
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Answer:
C 8^1/2
Step-by-step explanation:
Answer:
In fifteen years, Alexis would have 9200. In twenty years she would have 9600
Step-by-step explanation:
10% for interest of 8000= 80.
80 (interest for one year) * 15 (fifteen years)= 1200
1200 plus the original amount is 9200.
80 (interest for one year) * 20 ( twenty years)= 1600
1600 plus the original amount is 9600
A i believe hopefully that is the right answer
Answer:
a) $300 in interest
b) $1800 account total
Step-by-step explanation:
Interest = Principal x Rate x Time
I = 1500(.04)(5)
I = 300
A = P + I
1800 = 1500 + 300
