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Keith_Richards [23]
3 years ago
9

A square plot of land has a side length of 50 meters.

Mathematics
2 answers:
OLga [1]3 years ago
6 0
First, you would find the area of the whole square (based on the perimeter of the footpath). Since the footpath is 3 meters wide, you would add two 3 meter lengths to the length of the square plot to find the length of the entire square.
1) 50m + 3m + 3m = 56m length

Multiply 56 by 56, since that is the length of the square, and for the area of the square the formula is A = 2*L
2) 56m * 56m = 3136m squared

Then, find the area of the square plot in the inside.
3) 50m * 50m = 2500m squared

Subtract the two areas to find the area of the foot path going around the square plot.
4) 3136m^2 - 2500m^2 = 636m^2

Answer: the footpath has an area of 636 meters squared
V125BC [204]3 years ago
3 0

Answer:

636

Step-by-step explanation:

the area of the footpath=

(50m+3m+3m)^2-50^2

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A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

4 0
3 years ago
PLS HELP QUICK I WILL GIVE BRAINLIEST
Volgvan

Answer:

B

Step-by-step explanation:

The equation for B equals a negative answer

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