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lawyer [7]
2 years ago
15

An artillery shell is launched on a flat, horizontal field at an angle of α = 40.8° with respect to the horizontal and with an i

nitial speed of v0 = 346 m/s. What is the horizontal distance covered by the shell after 5.03 s of flight? Submit Answer Tries 0/12 What is the height of the shell at this moment?
Physics
1 answer:
Lina20 [59]2 years ago
8 0

Answer:

1317.4 m

Explanation:

We are given that

Angle=\alpha=40.8^{\circ}

Initial speed =v_0=346m/s

We have to find the horizontal distance covered  by the shell after 5.03 s.

Horizontal component of initial speed=v_{ox}=v_0cos\theta=346cos40.8=261.9m/s

Vertical component of initial speed=v_{oy}=346sin40.8=226.1m/s

Time=t=5.03 s

Horizontal distance =Horizontal\;velocity\times time

Using the  formula

Horizontal distance=261.9\times 5.03

Horizontal distance=1317.4 m

Hence, the horizontal distance covered by the shell=1317.4 m

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What happens to light waves at the interface between different media?
nevsk [136]

Answer:

Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.

Explanation:

Refractive motion is the impact of a light wave that travels from medium to medium in an angle away from normal, where the direction of light varies. Light is refracted when it crosses the air-to-glass interface and moves slower.

Hope this helps.

6 0
3 years ago
Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m
jeka57 [31]

Answer:

V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s     average speed

t = 7.2 / 7.25 = .993 sec      time to cross patch

a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2     or 1.5 m/s^2

8 0
2 years ago
A jet’s original velocity is 600 m/s. After 20 seconds accelerating at 8 m/s 2 , how
scoray [572]

Answer:

<h2>760 m/s</h2>

Explanation:

The jet's speed or final velocity can be found by using the formula

<h3>v = u + at</h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question we have

v = 600 + 20(8)

= 600 + 160

We have the final answer as

<h3>760 m/s</h3>

Hope this helps you

3 0
2 years ago
What determines the speed of a wave? Four sentences.
Ann [662]
The speed of waves are determined by the frequency of the push(wind). This really determines what the wave is being pushed by. If it were a Tsunami it would be by the frequency of the Tsunami if it were from the wind then the winds frequency would determine it's speed. Also the wavelength determines the speed because of the wight it has, but again something has to cause this wave to move.
5 0
3 years ago
4p
MariettaO [177]

Answer:

You can get w =Fxd 20Nx5m w=100N energy= w÷t 100N÷4s E=25J 3 you can apply 3J in one second

7 0
3 years ago
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