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Nat2105 [25]
3 years ago
8

- A person is on an elevator that moves

Physics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

The net force acting on the person is, F = 560 N

Explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

                                                          = 686 N

Therefore the mass of the person,

                                           m = W /g

                                               = 686 / 9.8

                                               = 70 kg

The net force acting on the person,

                                           F = mg - ma

                                               = 686 - 70 x 1.8

                                               = 560 N

Hence, the net force acting on the person is, F = 560 N

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Thermodynamic Processes
goblinko [34]

Answer:

A. Part a is the attachment

B. total work = 10.4kj

Explanation:

workdone=nRT1ln\frac{Vb}{Va}

T1 = constant temperature

nRT1 = PaVa = PbVb

We write equation as

workdone =(PaVa)ln\frac{Vb}{Va}

5ma = Pa, 5L = Va, Vb = 10L(temperature is doubled)

w1 = workdone =(5mpa*5L)ln\frac{10L}{5L}

W1 = 25 ln2

W1 = 25 x 0.693

= 17.327kj

The isochoric expansion has no change in volume. So,

W2 = 0

Isothermal compression

w3=nRT3ln\frac{Vd}{Vc}

T3 = constant temperature

nRT3 = PcVc = PdVd

workdone=(PcVc)ln\frac{Vd}{Vc}

Pc = 1mpa Vc = 10L Vd = 5L

w3=(1)(10)ln\frac{5L}{10L}

= 10x-0.693

= -6.93kj

Isochoric compression has no change in volume. Workdone w4 = 0

Total workdone = w1 + w2 + w3 + w4

= 17.33 + 0 + (-6.93) + 0

= 10.4kj

5 0
2 years ago
Two children sit on different sides of a seesaw. The first child of mass 27 kg sits 1.5 m from the center. How far must the seco
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Explanation:

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In some areas, farmers have installed windmills to generate electricity to run the farm. Some are generating a surplus of electr
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3 years ago
The mass of an electron is...
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4 0
3 years ago
Un lector de DVD, la velocidad de giro es de 5400 rpm. determina el valor velocidad angular en rad/s,la frecuencia y el periodo
zubka84 [21]

Responder:

A) ω = 565.56 rad / seg

B) f = 90Hz

C) 0.011111s

Explicación:

Dado que:

Velocidad = 5400 rpm (revolución por minuto)

La velocidad angular (ω) = 2πf

Donde f = frecuencia

ω = 5400 rev / minuto

1 minuto = 60 segundos

2πrad = I revolución

Por lo tanto,

ω = 5400 * (rev / min) * (1 min / 60s) * (2πrad / 1 rev)

ω = (5400 * 2πrad) / 60 s

ω = 10800πrad / 60 s

ω = 180πrad / seg

ω = 565.56 rad / seg

SI)

Dado que :

ω = 2πf

donde f = frecuencia, ω = velocidad angular en rad / s

f = ω / 2π

f = 565.56 / 2π

f = 90.011669

f = 90 Hz

C) Periodo (T)

Recordar T = 1 / f

Por lo tanto,

T = 1/90

T = 0.0111111s

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