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Nat2105 [25]
3 years ago
8

- A person is on an elevator that moves

Physics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

The net force acting on the person is, F = 560 N

Explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

                                                          = 686 N

Therefore the mass of the person,

                                           m = W /g

                                               = 686 / 9.8

                                               = 70 kg

The net force acting on the person,

                                           F = mg - ma

                                               = 686 - 70 x 1.8

                                               = 560 N

Hence, the net force acting on the person is, F = 560 N

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K_{t}=\frac{1}{2}*m*v^{2}\\v=w*r\\v=24rad/s*0.6m=14.4 \frac{m}{s}\\K_{t}=\frac{1}{2}*40kg*(14.4\frac{m}{s})^{2}\\K_{t}=4147.2J

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Now the work done by the friction is acting at the motion so the kinetic energy and the work of motion give the potential work so there we can find height

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