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Nat2105 [25]
3 years ago
8

- A person is on an elevator that moves

Physics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

The net force acting on the person is, F = 560 N

Explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

                                                          = 686 N

Therefore the mass of the person,

                                           m = W /g

                                               = 686 / 9.8

                                               = 70 kg

The net force acting on the person,

                                           F = mg - ma

                                               = 686 - 70 x 1.8

                                               = 560 N

Hence, the net force acting on the person is, F = 560 N

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The drawing shows a tire of radius R on a moving car
masha68 [24]

Answer:

 H / R = 2/3

Explanation:

Let's work this problem with the concepts of energy conservation. Let's start with point P, which we work as a particle.

Initial. Lowest point

          Em₀ = K = 1/2 m v²

Final. In the sought height

         Em_{f} = U = mg h

Energy is conserved

        Em₀ =  Em_{f}

        ½ m v² = m g h

        v² = 2 gh

Now let's work with the tire that is a cylinder with the axis of rotation in its center of mass

Initial. Lower

        Em₀ = K = ½ I w²

Final. Heights sought

        Emf = U = m g R

        Em₀ =  Em_{f}

       ½ I w² = m g R

The moment of inertial of a cylinder is

       I = I_{cm} + ½ m R²

      I= ½ I_{cm}  + ½ m R²

Linear and rotational speed are related

       v = w / R

       w = v / R

We replace

      ½ I_{cm}  w² + ½ m R² w²  = m g R

moment of inertia of the center of mass      

      I_{cm}  = ½ m R²

     ½ ½ m R² (v²/R²) + ½ m v² = m gR

    m v² ( ¼ + ½ ) = m g R

   

       v² = 4/3 g R

As they indicate that the linear velocity of the two points is equal, we equate the two equations

        2 g H = 4/3 g R

         H / R = 2/3

7 0
3 years ago
An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. Calculate the centripetal acce
tekilochka [14]

Given:

Object in circular motion 25 m/s

1 second to go quarter circle

Required:

Centripetal acceleration:

Solution:

Acceleration = v2/r

Where v is the velocity and r is the radian

Substituting the values into the equation,

Acceleration = v2/r = (25 m/s)2/(4*pi/180) = 8952.47 m2/s2

4 0
4 years ago
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?​
telo118 [61]
  • Force=12N
  • Work=9J

\\ \sf\longmapsto W=Fd

\\ \sf\longmapsto d=\dfrac{W}{F}

\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m

6 0
3 years ago
Read 2 more answers
Which of the following hypotheses is both falsifiable and testable?
rosijanka [135]
B. If all plants are watered at least once a day then they will all grow at least 1 cm a day.

All plants grow at different rates.

Hope this helps! XD
5 0
3 years ago
Read 2 more answers
Use the equation for magnetic force on a moving charge to derive the equation for magnetic force on a current carrying wire. Sho
max2010maxim [7]

Answer:

The formula comes from Lorentz force law which includes both the electric and magnetic field. If the electric field is zero, the force law for just the magnetic field is <u>F=q(ν×B</u>) . Here, F  is force and is a vector because the force acts in a direction.  q  is the charge of the particle.  v  is velocity and is a vector because the particle is moving in some direction.  B is the magnetic flux density.

We can derive an expression for the magnetic force on a current by taking a sum of the magnetic forces on individual charges. (The forces add because they are in the same direction.) The force on an individual charge moving at the drift velocity vd.  Since the magnitude of B is constant at every line element of the loop (circle) and it dot product with the line element is B dl everywhere, therefore

                                                  ∮B dl=μ0 I

                                                  B ∮dl=μ0 I

                                                  B 2πr=μ0 I

                                                   B=μ02πr Id=μ0/4π I dl×rr3

Since, r can be written as r=(rcosθ,rsinθ,z) and dl as dl=(dl,0,0) And now, if we take the cross product we would get

                                               dl×r=−z dlj^+rsinθk^

and therefore the magnitude of dB is equal to

dB=μ0/4π I |dl×r|/r3=μ0/4π I z2+r2sin2θ−−−−−−−−−−√dl/r3

Thus, magnetic field is depending on r,θ,z.

Learn more about Force here-

brainly.com/question/2855467

#SPJ4

7 0
2 years ago
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