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SOVA2 [1]
3 years ago
8

Evidence that the cosmic background radiation really is the remnant of a Big Bang comes from predicting characteristics of remna

nt radiation from the Big Bang and comparing these predictions with observations. Four of the five statements below are real. Which one is fictitious?
Physics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

B) The cosmic background radiation is expected to contain spectral lines of hydrogen and helium, and it does.

Explanation:

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Which statement best describes perigee? A) The closest point in Earth's orbit of the Sun. B) The farthest point in the Moon's or
iragen [17]
The correct answer is D) The closet point in the Moon's orbit to Earth

This does not refer to the Moon only. It refers to any satellite and to its closest point to Earth.
3 0
3 years ago
If you cut a piece of wood in half, each half would have *
Anon25 [30]

Answer:

c

Explanation:

let's assume that you are splitting the piece of wood horizontally. This would not change the density of the wood at all, only the length. I rest my case. Ur awesome and have an amazing day.

7 0
3 years ago
What could serve as ballast for a balloon? Help pls...thx
I am Lyosha [343]
With the advent of the plastic balloon and the beginning of the unmanned ... That would lead to a more sophisticated ballast system that uses fine steel or iron
6 0
3 years ago
Tarzan has foolishly gotten himself into another scrape with the animals and must be rescued once again by Jane. The 60.0 kg Jan
Brut [27]

Complete part of Question: What is Jane's (and the vine's) angular speed just before she grabs Tarzan

Answer:

Jane's (and the vine's) angular speed just before she grabs Tarzan, w = 1.267 rad/s

Explanation:

According to the law of energy conservation:

Total change in kinetic energy = Total change in potential energy

Mass of Jane = 60 kg

Mass of the vine = 32 kg

Mass of Tarzan = 72 kg

Height of Tarzan = 5.50 m

Length of the vine = 8.50 m

Jane's change in gravitational potential energy,

U_J = 60 * 9.8 * 5.5\\U_J = 3234 J

Vine's gravitational potential energy,

U_v = Mgh/2\\U_v = 32*9.8*5.5/2\\U_v = 862.4J

Vine's Kinetic energy :

KE_V = 0.5 I w^{2} \\I_V = \frac{ML^2}{3} = \frac{32 * 8.5^2}{3} = 770.67 kg m^2\\ KE_V = 0.5 *770.67 * w^{2}\\KE_V = 385.33 w^{2}

Jane's Kinetic energy:

KE_J = 0.5m(wL)^2\\KE_J = 0.5*60(w * 8.5)^2\\KE_J = 2167.5 w^2

U_J + U_V = KE_J + KE_V

3234 + 862.4 = 2167.5w² + 385.33w²

4096.4 = 2552.83w²

w² = 4096.4/2552.83

w² = 1.605

w = √1.605

w = 1.267 rad/s

5 0
3 years ago
What can you caculate if you know the frequency and speed of a wave
Mila [183]

Frequency and speed = wavelength.

4 0
4 years ago
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