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3 years ago

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Evidence that the cosmic background radiation really is the remnant of a Big Bang comes from predicting characteristics of remna

nt radiation from the Big Bang and comparing these predictions with observations. Four of the five statements below are real. Which one is fictitious?

1 answer:

mario62 [17]3 years ago

3 0

Answer:

B) The cosmic background radiation is expected to contain spectral lines of hydrogen and helium, and it does.

Explanation:

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Harold is using what he knows about cause-and-effect relationships to write a paper explaining cloud shape. How could he describ

Gre4nikov [31]

Answer:c

Explanation:

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3 years ago

A circular conducting loop with a radius of 0.10 m and a small gap filled with a 10.0 ȍresistor is oriented in the xy-plane. If

lidiya [134]

Answer:

The magnitude of the current is 5.45 mA.

Explanation:

Given that,

Resistance = 10.0 ohm

Radius = 0.10 m

Magnetic field = 1.0 T

Angle = 30°

Increase magnetic field = 7.0 T

Time t = 3.0 s

Number of turns = 1

We need to calculate the initial flux

Using formula of flux

$\phi=NB_{1}A\cos\theta$

Put the value into the formula

$\phi=1\times1.0\times\pi\times(0.10)^2\times\cos30^{\circ}$

$\phi=1\times1.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}$

$\phi=0.027\ wb$

We need to calculate the final flux

$\phi=1\times7.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}$

$\phi=0.1904\ wb$

We need to calculate the induced emf

Using formula of emf

$\epsilon=\dfrac{\phi_{f}-\phi_{i}}{t}$

Put the value into the formula

$\epsilon=\dfrac{0.1904-0.027}{3.0}$

$\epsilon=0.0545\ V$

We need to calculate the current

Using formula of current

$I=\dfrac{\epsilon}{R}$

Put the value into the formula

$I=\dfrac{0.0545}{10.0}$

$I=5.45\ mA$

Hence, The magnitude of the current is 5.45 mA.

4 0

3 years ago

Which events are associated with convergent boundaries? Check all that apply. formation of island chains creation of mid-ocean r

barxatty [35]

Answer:

- creation of mid-ocean ridges

-creation of new mountains

-formation of earthquakes

-formation of volcanoes

Convergent boundary plate tectonic involves collisions between oceanic and continental plates. The thinner and less denser oceanic plate overriden by the thicker and more denser continental plate. The oceanic plate is forced down the mantle, this event is known as subduction. The magma present in the mantle causes melting of subduction plates. The magma enters inside these plates through pores. This magma plate becomes bouyant and moves upwards. The molten magma causes volcanic eruptions along with earthquakes. If the magma solidifies in the subduction zone it creates mid ocean ridges. The mountains are formed near the continents when the magma after volcanic eruption gets cooled and solidified.

4 0

3 years ago

Read 2 more answers

According to Newtons third law of motion when one object exerts a force on a second object what is true about the forces?

fomenos

Answer:

D.They are equal in magnitude and opposite in direction

Explanation:

Newton's third law states that the action force is always associated with a reaction force.
When a body 'A' exerts a force on body 'B', it is called the force of action.
When the body 'B' in turn resist the force of 'A' is called the reaction force. It is the reactive force acted upon by the body 'B' on 'A'.
This reaction force is equal in magnitude of the action force.
If the two bodies remain in the same horizontal line, the 'A' exerts a force in the direction towards 'B' and the body 'B' exerts a reaction force in the direction towards 'A'.
Hence, the two forces that are exerted by the bodies are equal in magnitude and opposite in direction.

7 0

3 years ago

Two masses are connected by a string which passes over a pulley with negligible mass and friction. One mass hangs vertically and

monitta

Answer:

$a=2,5m/s^2$

Explanation:

From the question we are told that:

Coefficient of kinetic friction $\mu= 0.200$

Vertical Mass $M_v=3kg$

Horizontal mass $M_h=3.00kg$

Generally the equation for kinetic force $F_k$ is mathematically given by

$F_k=\mu N\\F_k=0.2*3\\F_k=0.6$

Generally the equation for T is mathematically given by

$For M_v=3kg3g-T=3a$

For $M_h=3kg$

$T=M_v V+F_k\\T=3.0a+0.6$

Therefore substituting

$3-3a-0.6=3a\\2.4g=6a$

$a=2,5m/s^2$

3 0

3 years ago