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Volgvan
3 years ago
11

Jake spends 2 hours on each homework assignment and he had 3 assignments each day. Orlando spends 2 hours on each homework assig

nment and he had 2 homework assignments each day.
How much time will Jake and Orlando spend doing homework after 30 days?
Mathematics
2 answers:
Rama09 [41]3 years ago
5 0
Jake will spend 180 hours on homework assignments after 30 days and Orlando will spend 120 hours on homework assignments after 30 days hope this helps :)  (Jake:2 hours X 30 days = 180hrs) (Orlando:4 hours X 30 days= 120hrs)
fomenos3 years ago
4 0
Jake: one hundred and eighty hours
Orlando: one hundred and twenty hours

total: three hundred hours
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1. m = 1/2

2. m = 2

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Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

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Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

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P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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