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vovangra [49]
2 years ago
13

What is the Scale factor of 35 to 42

Mathematics
1 answer:
polet [3.4K]2 years ago
8 0

QUESTION. What is the Scale factor of 35 to 42

--------------------------------------

\boxed {\tt 25/35}

---------------------------------------

The Scale Factor of 35/42 is the relative difference of one fraction or number (a) to another fraction or number prime (a′). In other words, 35/42 is what you multiply (number a) by to get (number a prime).

In a multiplication problem, we have a multiplier, multiplicand, and a product. You could say that (a) is the multiplier, the Scale Factor of 35/42 is the multiplicand, and (a′) is the product:

multiplier × multiplicand = product

multiplier × scale factor = product

a × 35/42 = a′

In the calculator below, you can enter the multiplier (a) as a fraction. We will then multiply it by the Scale Factor of 35/42 and give you the product (a′) in its simplest form possible.

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Solve –5√ x = –15. <br><br><br><br> A. x = –7<br> B. x = –9<br> C. x = 7<br> D. x = 9
Pie
-5√x = -15
   -5       -5
   √x = 3
      x = 9

The answer is D.
3 0
3 years ago
Read 2 more answers
Is there a series of rigid transformations that could map TriangleKLP to TriangleQNM? If so, which transformations? No, Triangle
poizon [28]

Answer:

C. Yes, Triangle KLP can be reflected across the line containing KP and then translated so that P is mapped to M

Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
A train leaves thorn junction at 1:25 p.m. and arrives in niles at 3:05 p.m. the train makes two stops along the route for a tot
KonstantinChe [14]

The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.

<h3>What is speed?</h3>

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

\rm Speed = \dfrac{Distance}{Time}

A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.

A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.

This train does not make any stops.

Let the speed of both trains be equal.

Then the time taken by the first train will be

t₁ = 3:05 p.m. - 1:25 p.m.

t₁ = 1 hour 40 minutes

Then the time taken by the second train will be

t₂ = 1:40 - 00:15

t₂ = 1:25 = 1 hour 25 minutes

The time when the second train is at Niles junction will be

→ 4:30 p.m. + 1:25

→ 5:55 p.m.

More about the speed link is given below.

brainly.com/question/7359669

#SPJ1

3 0
2 years ago
Use the graph to answer the questions help!
max2010maxim [7]

Answer:

0; 2; 6; 0 or -1

Step-by-step explanation:

If the question says "f(a)=" they are asking for the y value with the given x such as the two first ones.

If it's "f(x)=a than x=" they are asking you what x is when the (bolded) x is a given value.

5 0
3 years ago
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{first sol'n}&11&x&11x\\&#10;\textit{second sol'n}&4&0.55&2.20\\&#10;------&-----&-------&-------\\&#10;mixture&y&0.77&0.77y&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;11+4=y\implies 15=\boxed{y}\\&#10;11x+2.2=0.77y\\&#10;----------\\&#10;11x+2.2=0.77\cdot \boxed{15}&#10;\end{cases}

solve for "x"
6 0
3 years ago
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