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3 years ago

Solve the equation 3x^2+24x=0 for x

Mathematics

2 answers:

horrorfan [7]3 years ago

7 0

Answer:

{0,-8}

Step-by-step explanation:

Factor!

3x(x+8)=0

3x=0 or x+8=0

x=0 or x=-8

jok3333 [9.3K]3 years ago

3 0

Answer:

x=0 x =-8

Step-by-step explanation:

3x^2+24x=0

Factour out a 3x

3x(x+8) =0

Using the zero product property

3x =0 x+8 =0

x=0 x+8-8 =0-8

x=0 x =-8

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vampirchik [111]

Answer:

Step-by-step explanation:

Because when you add up the points you would get (4,3)

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2 years ago

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What are the zeros of the function g(x) = (x + 6) (x – 4)(x + 2) ?

vitfil [10]

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Answer:

x in {-6, -2, 4}

Step-by-step explanation:

The zero product rule tells you that a product will be zero if and only if one of the factors is zero. These binomial factors are zero when x has a value that is opposite the constant of the binomial.

x +6 = 0 ⇒ x = -6

x -4 = 0 ⇒ x = 4

x +2 = 0 ⇒ x = -2

The zeros of the function are the x-values -6, -2, and 4.

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3 years ago

P(x)=x-3 g(x) = 2x-5 Find the following. (p ° q)(5)= and (q ° p)(5)=

deff fn [24]

Answer:

(p∘q)(5) = 2

(q∘p)(5) = -1

Step-by-step explanation:

The composition of functions can be written a little differently, perhaps making it easier to understand.

(p∘q)(x) = p(q(x))

(p∘q)(5) = p(q(5)) = p(2·5 -5) = p(5) = 5 -3

(p∘q)(5) = 2

(q∘p)(5) = q(p(5)) = q(2) = 2·2 -5

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3 years ago

Identify the underlined place in 83.5851. Then round to the nearest thousandth

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The underlined place in 83.5851 which is then rounded to the nearest thousandth is A. tenth; 83.585 .

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4 years ago

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27 divided by N has a remainder of 3. How many different positive integers could n be?

myrzilka [38]

Solving this question will involve basic division knowledge.

The different positive integer values of n are; 4,6,8,12,24

From knowledge on division, we know that when 27 is divided by N and we have 3 as remainder, we can express it as;

$\frac{27}{n}$ = quotient + $\frac{3}{n}$

Now let us rearrange to get;

$\frac{27}{n}$ - $\frac{3}{n}$ = quotient

this gives;

$\frac{24}{n}$ = quotient

Now to get how many positive integers can be n, it means all positive values of the quotient must be positive integers as well.

Factors of 24 are; 1, 2, 3, 4, 6, 8, 12, 24

Thus, the possible positive integers will come from this list.

But we can't make use of 1,2,3 as possible values of n because when we divide with 27, we will get either an exact value or 1 as the remainder.

Thus the possible positive integer values of n are; 4,6,8,12,24

Read more at; brainly.in/question/20088076

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3 years ago

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