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kumpel [21]
3 years ago
6

Help I missed 6 weeks of school bc of a injury need help!!!

Mathematics
1 answer:
Alex787 [66]3 years ago
5 0
C for #7. Hopefully someone can help you with 5&6
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It would help the rabbit by blending in with the environment and avoiding predators.

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Can somebody please help with this?
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Answer:

  A.  2.9π(9²)

Step-by-step explanation:

You are expected to know that the area of a circle is given by the formula ...

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and that r in the formula represents the radius of the circle, half the diameter.

The area of the circular base of the cylinder is the area of a circle with a radius of 9 feet. It will be ...

  A = π(9²)

When that is multiplied by the height of the cylinder to find its volume, you have ...

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Jordan’s father is three times as old as Jordan. The sum of their age combined is 48. How old is Jordan?
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Suppose a sample of 972972 tenth graders is drawn. Of the students sampled, 700700 read above the eighth grade level. Using the
max2010maxim [7]

Answer:

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

972 students, 700 read above the eight grade level. We want the confidence interver for the proportion of those who read at or below the 8th grade level. 972 - 700 = 272, so n = 972, \pi = \frac{272}{972} = 0.28

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.259

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.301

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

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3 years ago
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