Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
Answer:
y = (-1/6)x
Step-by-step explanation:
As we move from (-3, 0.5) to (3, -0.5), x increases by 6 and y decreases by 1.
Hence, the slope of this line is m = rise / run = -1/6.
Starting with the slope-intercept form of the equation of a straight line, we have:
y = mx + b. We substitute 0.5 for y, -3 for x and -1/6 for m, obtaining:
0.5 = (-1/6)(-3) - b, or:
0.5 = 0.5 - b. Then b = 0, and the desired equation is
y = (-1/6)x
It has 5 sides.
Hope this helps:)
Answer:
5
Step-by-step explanation:
Simplify
Let's simplify step-by-step.
x(5)−3(x−4)
Distribute:
=x(5)+(−3)(x)+(−3)(−4)
=5x+−3x+12
Combine Like Terms:
=5x+−3x+12
=(5x+−3x)+(12)
=2x+12
Answer:
=2x+12
