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3 years ago

What is the answer to the equation -2y-2

Mathematics

1 answer:

Elanso [62]3 years ago

7 0

Answer:-1

Step-by-step explanation:You do reverse operation so negative 2Y means multiplication so you divide two -2 sides so positive two divided by -2 is -1

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What is the slope of a line perpendicular to the line whose equation is 6x+4y=-56

alex41 [277]

Answer:

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.Step-by-step explanation:

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5 0

2 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

2 years ago

Graph B

lara [203]

Answer/Step-by-step explanation:

Slope (m) = rise/run

y-intercept (b) = starting value or the point on the y-axis where the line cuts across

✔️Slope (m) of skater 1:

Rise = 45

Run = 7.5

Slope (m) = 45/7.5 = 6

✔️ y-intercept (b) of Skater 1:

b = 0 (the y-axis is intercepted at 0)

✔️Skater 1 linear function in slope-intercept form, y = mx + b

Substitute m = 6 and b = 0 into y = mx + b

Linear function: y = 6x + 0

y = 6x

✔️Slope (m) of skater 2:

Rise = 30

Run = 15

Slope (m) = 30/15 = 2

✔️ y-intercept (b) of Skater 2:

b = 0 (the y-axis is intercepted at 0)

✔️Skater 2 linear function in slope-intercept form, y = mx + b

Substitute m = 2 and b = 0 into y = mx + b

Linear function: y = 2x + 0

y = 2x

7 0

2 years ago

What is the domain of the function Y=square root <br> x+6 - 72

Evgen [1.6K]

Answer:

the answer is negative infinity to infinity since the range is -66 to infinity

3 0

2 years ago

Find an equation of the tangent line to f(x) = 5x2 − 2x + 10 at x = 7.

laiz [17]

Answer:

$y=68x-235$

Step-by-step explanation:

$f(x) = 5x^2-2x + 10$

Differentiate:

$\implies f'(x)=10x-2$

Substitute $x=7$ into $f'(x)$ :

$\implies f'(7)=10(7)-2=68$

Therefore, 68 is the gradient of the tangent line at x=7:

$\implies y-y_1=68(x-x_1)$

when $x=7$ , $y=5(7)^2-2(7)+10=241$

$\implies y-241=68(x-7)$

$\implies y=68x-235$

4 0

2 years ago