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andrezito [222]
3 years ago
14

Is y =1 a function? and if so what is the parent function?

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0
The function is equal to y(an unknown number) is equal to 1 times a(another unknown number)But since anything times one is itself, it is equal to y=y so that means NO it is not a function.
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Find the sum of the geometric series 40 + 40(1.005) + 40(1.005)^2 + ⋯ + 40(1.005)^11.
KiRa [710]

Answer:

The sum is 493.4

Step-by-step explanation:

In order to find the value of the sum, you have to apply the geometric series formula, which is:

\sum_{i=1}^{n} ar^{i-1} = \frac{a(1-r^{n})}{1-r}

where i is the starting point, n is the number of terms, a is the first term and r is the common ratio.

The finite geometric series converges to the expression in the right side of the equation. Therefore, you don't need to calculate all the terms. You can use the expression directly.

In this case:

a=40

b= 1.005

n=12 (because the first term is 40 and the last term is 40(1.005)^11 )

Replacing in the formula:

\frac{a(1-r^{n})}{1-r} = \frac{40(1-1.005^{12})}{1-1.005}

Solving it:

The sum is 493.4

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3 years ago
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4 years ago
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8 0
2 years ago
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3 years ago
1. Find the distance between two
BigorU [14]

Answer:

\mathrm{D)\:}9.4\: \mathrm{units}

Step-by-step explanation:

<u>Solution 1:</u>

Notice the x coordinate of both points are equal, meaning both points are on a vertical line. The distance between two points on a vertical line is the absolute difference of their y-coordinates. The absolute difference between 4.7 and -4.7 is |4.7-4.7|=\fbox{$9.4$}.

<u>Solution 2:</u>

The distance between two points (x_1,y_1) and (x_2,y_2) is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Plugging in given values, we have:

d=\sqrt{(-2.6-(-2.6))^2+(4.7-(-4.7))^2},\\d=\fbox{$9.4$}.

8 0
3 years ago
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