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3 years ago

9

Help with this question, please ASAP!! I need help!!

1 answer:

SashulF [63]3 years ago

6 0

i did this before the answer is choice B

I hope this helps :D

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Find the constant of proportionality k. Then write an equation for the relationship between x and y

ExtremeBDS [4]

Question:

Find the constant of proportionality k. Then write an equation for the relationship between x and y

$\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}$

Answer:

(a) $k = 5$

(b) $y = 5x$

Step-by-step explanation:

Given

$\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}$

Solving (a): The constant of proportionality:

Pick any two corresponding x and y values

$(x_1,y_1) = (2,10)$

$(x_2,y_2) = (6,30)$

The constant of proportionality k is:

$k = \frac{y_2 - y_1}{x_2 - x_1}$

$k = \frac{30-10}{6-2}$

$k = \frac{20}{4}$

$k = 5$

Solving (b): The equation

In (a), we have:

$(x_1,y_1) = (2,10)$

k can also be expressed as:

$k = \frac{y- y_1}{x- x_1}$

Substitute values for x1, y1 and k

$5 = \frac{y- 10}{x- 2}$

Cross multiply:

$y - 10 = 5(x - 2)$

Open bracket

$y - 10 = 5x - 10$

Add 10 to both sides

$y - 10 +10= 5x - 10+10$

$y = 5x$

6 0

3 years ago

Would it be factoring a polynomial,

alukav5142 [94]

Factoring a polynomial

3 0

3 years ago

Fifty-four percent of what number is 162

baherus [9]

300 would be your answer.

5 0

3 years ago

Read 2 more answers

Please help me I’m so lost !!!!

Tasya [4]

Answer:

$4095$

Step-by-step explanation:

$\sum _{n=1}^63\left(4^{n-1}\right)\:$

$\sum _{n=1}^63\cdot \:4^{n-1}$

Compute general progression:

$\frac{3\cdot \:4^{\left(n+1\right)-1}}{3\cdot \:4^{n-1}}=4$

$r=4\\$

$a_1=3\cdot \:4^{1-1}$

$a_1=3$

nth term is computed by:

$r=4,\:a_n=3\cdot \:4^{n-1}$

plug in the values $n=6,\:\spacea_1=3,\:\spacer=4$ :

$=3\cdot \frac{1-4^6}{1-4}$

$=4095$

5 0

3 years ago

7. Is the simplified form of 2 square root of 3 ⋅ 2 square root of 6 rational? (1 point)

Lynna [10]

Answer:

Yes

Step-by-step explanation:

I've done this before.

6 0

3 years ago