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zloy xaker [14]
3 years ago
10

A railroad car moving at a speed of 3.41 m/s overtakes, collides, and couples with two coupled railroad cars moving in the same

direction at 1.40 m/s. All cars have a mass of mass 1.07 x 10^5 kg. Determine the following. (a) speed of the three coupled cars after the collision (Give your answer to at least two decimal places.) (b) kinetic energy lost in the collision
Physics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

2.07 m/s

Explanation:

m = 1.07 x 10^5 kg, u1 = 3.41 m/s, u2 = 1.4 m/s

Let the speed of three coupled car after collision is v

Use conservation of momentum

m x u1 + 2 m x u2 = 3 m x v

u1 + 2 u2 = 3 v

3.41 + 2 x 1.4 = 3 v

v = 2.07 m/s

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The jet in the problem has, taking east as positive direction:

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The displacement of the jet can be found using another suvat equation

s=ut+\frac{1}{2}at^2

where

s is the displacement

u is the initial velocity

a is the acceleration

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For the jet in this problem,

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

t = 10 s is the time

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