Answer:
a) t = 1.75 s
b) x = 31.5 m
Explanation:
a) The time at which Tom should drop the net can be found using the following equation:

Where:
: is the final height = 0
y₀: is the initial height = 15 m
g: is the gravity = 9.81 m/s²
: is the initial vertical velocity of the net = 0 (it is dropped from rest)


Hence, Tom should drop the net at 1.75 s before Jerry is under the bridge.
b) We can find the distance at which is Jerry when Tom drops the net as follows:


Then, Jerry is at 31.5 meters from the bridge when Jerry drops the net.
I hope it helps you!
The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
By the newtons Second Law:
F = ma
Solving for m:
m = F / a
m = 100 N / 2 m/s²
<h3>m = 50 kg → ANSWER</h3>
Answer:
rpm= 916.7436 rev/min
Explanation:
First determine the perimeter of the wheel, to know the horizontal distance it travels in a revolution:
perimeter= π×diameter= π × 22 inches × 0.0254(m/inche)= 1.7555m
Time we divide the speed of the car, which is the distance traveled horizontally over time unit, by the perimeter of the wheel that is the horizontal distance traveled in a revolution, this dates us the revolutions over the time unit:
revolutions per time= velocity/perimeter
velocity= (60 mi/hr) × (1609.34m/mi) = 96560m/h
revolutions per time= (96560.6m/h) / (1.7555m)= 55004.614 rev/hr
rpm= (55004.614 rev/hr) × (hr/60min)= 916.7436 rev/min
Answer:
Since (average) acceleration = (change in velocity)/(time it takes), the car's acceleration = (100 km/h)/(10 s) = 10 km/h/s. This means that, on the average, the car's velocity changed by 10 km/h each second.
Explanation: