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valina [46]
3 years ago
11

I have trouble with the converting

Mathematics
1 answer:
Gnom [1K]3 years ago
7 0
HI,
3 yd= 108 in
24 ft = 8 yd
56 ft= 18 yd 6 ft
12 ft 6 in = 216 in ( im not 100% sure on this one)
i hope this helped you 
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Evaluate A/B for a = 1/2 and b = -3/7
bonufazy [111]

Answer:

-7/6

Step-by-step explanation:

If a = 1/2 and b = -3/7, then your given:

1/2 divided by -3/7=

-7/2*3=

-7/6

Sorry if its a bit unclears

4 0
3 years ago
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MAXImum [283]
30÷4=7.5
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3 years ago
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Factor completely 56a2b3 − 35ab.
VMariaS [17]

I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.


Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b.  Now, it's shortened to be 56ab2-35.


Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.


I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.


So, that means the answer is 56ab2-35.


I hope this helps!! (And makes sense)

5 0
3 years ago
(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
5 0
3 years ago
What is the area of a regular hexagon with a side length of 6 yd? Enter your answer in the box. Round only your final answer to
tatuchka [14]
Your answer would be 93.53
5 0
3 years ago
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