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valina [46]
3 years ago
11

I have trouble with the converting

Mathematics
1 answer:
Gnom [1K]3 years ago
7 0
HI,
3 yd= 108 in
24 ft = 8 yd
56 ft= 18 yd 6 ft
12 ft 6 in = 216 in ( im not 100% sure on this one)
i hope this helped you 
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PLEASE HELP. WILL GIVE BRAINLIEST FOR CORRECT ANSWER
lozanna [386]
Are of shaded region = area of circle - area of segment
= \pi {r}^{2}  - ((\alpha  \div 360) \times \pi \times  {r}^{2} )
= \pi {r}^{2} (1 -  \alpha  \div 360)
r = 8.35 \\  \alpha  = 100
= 158.1666....
rounding \: up
area \: of \: shaded \: region \:  = 158.2 \: \: square ft
6 0
3 years ago
What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)
nordsb [41]
Y = A cos(Bx + C)
A - amplitude
\frac{2\pi}{B} - period
- \frac{C}{B} - phase shift

y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}
\\
\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}
\\
\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}

Amplitude: 5
Period: \frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi
Phase shift: - \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}
3 0
3 years ago
Is it ok you guys maybe do this one too sorry...<br> (−6)(−0.4)(−0.5)
olchik [2.2K]
(-6)(-0.4)(-0.5) = (-1)6⋅4⋅5⋅10⁻² = -1.2
5 0
3 years ago
Find an expression for the area enclosed by quadrilateral ABCD below.
Helga [31]
  • ∆ABD is right angled hence area:-

\\ \sf\longmapsto \dfrac{1}{2}bh

\\ \sf\longmapsto \dfrac{1}{2}(4x)(3x)

\\ \sf\longmapsto \dfrac{1}{2}(12x^2)

\\ \sf\longmapsto 6x^2

There is only one option containing 6x^2 i.e Option D.

Hence without calculating further

Option D is correct

6 0
3 years ago
Read 2 more answers
I will mark Brainlyst
suter [353]

Answer:

A because of its larger range

Step-by-step explanation:

8 0
3 years ago
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