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Vesnalui [34]
2 years ago
9

Ok last question i asked was answered by a scam bot so here i go again

Mathematics
1 answer:
Daniel [21]2 years ago
5 0

Answer:

Make 7 jumps, each 0.2 units long. You end at 1.4, which is the product of 7 and 0.2.

Sorry to hear about the bot! Hope this helps!

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(x-2)^3+13=-112<br> <img src="https://tex.z-dn.net/?f=%28x-2%29%5E3%2B13%3D-112" id="TexFormula1" title="(x-2)^3+13=-112" alt="(
yKpoI14uk [10]

Answer:

x = -3

Step-by-step explanation:

(x - 2)^3 + 13 = -112

Subtract 13 from both sides

(x - 2)^3  = -125

Take the cube root of both sides

x - 2 = -5

Add 2 to both sides

x = -3

7 0
3 years ago
Point H(9, 1) is reflected across the x-axis. Which statements about H’ is true?
Elza [17]

Answer:

b and d

Step-by-step explanation:

Under a reflection in the x - axis

a point (x, y ) → (x, - y ) , then

H (9, 1 ) → H' (9, - 1 )

the x- coordinate is 9 → b

the y- coordinate is - 1 → d

7 0
3 years ago
How do you round 26.2 to the nearest tenth of a kilometer?
Fittoniya [83]
The answer would be 26 because .1-4 rounds down, 5-9 rounds up
6 0
3 years ago
Please find the answer my math teacher doesn’t know how to explain!
const2013 [10]

Answer:

68.8

Step-by-step explanation:

(a+b)h/2

12.9+8.6 *6.4/2

8 0
3 years ago
Please help with this asappppppppll
Alenkinab [10]

We are given with a circle and we need to find the <em>equation of the circle</em> , but first let's recall that , the equation of a circle with radius<em> 'r'</em> and centre at <em>(h,k) </em>is given by {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}

Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here <em>(h,k) = (0,0)</em> .Which means that the centre is located at the point whose coordinates are<em> (0,0)</em> which is also known as origin . Now , finding the equation of the circle :-

{:\implies \quad \sf (x-0)^{2}+(y-0)^{2}=(9)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{x^{2}+y^{2}=81}}}

<em>This is the required equation of Circle</em>

7 0
3 years ago
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