What is the circumference of a circle

Mathematics

1 answer:

borishaifa [10]3 years ago

5 0

C=2πr

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7.64=7+ blank +4/100

mash [69]

Answer:

6/10 or 60/100

Step-by-step explanation:

4/100=0.04 So if you add that to 7 you would have 7.04 and 7.64-7.04 is 0.6 which is 6/10 or 60/100 in fraction form.

5 0

3 years ago

Looking at the fraction 6/3, what type of fraction is it?

scoray [572]

Answer:

The fraction '6/3' is an improper fraction

Explanation:

There are 3 types of fractions

Improper fraction
Mixed fraction
Proper fraction

The fraction '6/3' is an improper fraction because its numerator is larger than the denominator. If we were looking at 2/3, that fraction would've been classified as a proper fraction because its numerator is smaller than the denominator. An interesting fact is that an improper fraction can be converted to a mixed fraction, even if it is a whole number. 6/3 can be written as 1 3/3, which is 6/3. To convert mixed fraction to improper fraction, simply multiply the denominator and add the numerator.

Hoped this helped.

$BrainiacUser1357$

5 0

3 years ago

Read 2 more answers

Which point lies on the graph of y=2(1/2^x?

qaws [65]

Answer:

(0,0)

Step-by-step explanation:

8 0

3 years ago

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

Substract the following :(4x^3+6x+9)-(-15x^2+7x-2)

STatiana [176]

To solve this, we need to rearrange to get like terms by each other. Remember to distribute the negative.

$4x^3+6x+9+15x^2-7x+2

4x^3+15x^2+6x-7x+9+2

4x^3+15x^2-x+11$

7 0

3 years ago