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NNADVOKAT [17]
3 years ago
6

PLEASE HELP FAST!!!!!!!!

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

Option B. -j = -h/-k is not correct

Step-by-step explanation:

As from the given scenario both the negative signs will be cancelled out giving positive j : -h/-k = -j

First option has: -j = -h/k In this case also the negative sign from both sides would be cancelled out.

Second option has: -h/-k = -j In this case negative signs cannot be cancelled out.

Third option has: h/-k = -j , negative sign would be cancelled from both sides.

Fourth option has: h/k = j , no negative sign on either side.

i hope it will help you!

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Step-by-step explanation:

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2 years ago
A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row. All the lights start out off. The first
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<u>Solution-</u>

A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row.

As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

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2 years ago
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A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30,
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Answer:

b) The margin of error is approximately 3.24

e) The critical value is 1.7921.

Step-by-step explanation:

<u>Step(i</u>):-

Given sample size 'n' =20

Given sample standard deviation 's' = 10

<u><em> Margin of error </em></u>

<u><em>The margin of error is determined by</em></u>

<u><em /></u>M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }<u><em /></u>

<em>The level of significance ∝ =0.95</em>

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Step(ii):-

<u><em> Margin of error </em></u>

<u><em>The margin of error is determined by</em></u>

<u><em /></u>M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }<u><em /></u>

<u><em>Given another sample size n =30</em></u>

<em>The level of significance ∝ =0.95</em>

<em>The degrees of freedom = n-1 = 30-1=29</em>

t₀.₉₅ = 1.70

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<u><em>Margin of error = 3.24</em></u>

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