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NNADVOKAT [17]
3 years ago
6

PLEASE HELP FAST!!!!!!!!

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

Option B. -j = -h/-k is not correct

Step-by-step explanation:

As from the given scenario both the negative signs will be cancelled out giving positive j : -h/-k = -j

First option has: -j = -h/k In this case also the negative sign from both sides would be cancelled out.

Second option has: -h/-k = -j In this case negative signs cannot be cancelled out.

Third option has: h/-k = -j , negative sign would be cancelled from both sides.

Fourth option has: h/k = j , no negative sign on either side.

i hope it will help you!

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Answer:

y = 8

General Formulas and Concepts:

<u>Algebra I</u>

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Step-by-step explanation:

What the question is asking is for the y-value when the x-value is equal. According to the graph, when x = 6, y = 8. Therefore, y = 8.

8 0
3 years ago
If (x-1)/(x)=20 then x=
nadezda [96]
D:x\neq0\\\\\frac{x-1}{x}=20\ \ \ \ |cross\ multiply\\\\20x=x-1\ \ \ \ |subtract\ x\ from\ both\ sides\\\\19x=-1\ \ \ \ \ \ |divide\ both\ sides\ by\ 19\\\\\boxed{x=-\frac{1}{19}}

6 0
3 years ago
Read 2 more answers
Suppose a class of 50 students has 20 males and 30 females. The insturctor will pick 1 (different) student to compete in 3 diffe
Pie

Answer:

Step-by-step explanation:

Total = 50

Males = 20

Females = 30

a) P(exactly 1 female) = P(1 female , 2 male)

(30C1 * 20C2) / (50C3) = 30*190/19,600 = 0.2908

b) P(at least 2 males) = 1 - (P(0 males) + P(1 males))

= 1 - 30C3 * 20C0/50C3 - 30C2 * 20C1/50C3

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4 0
3 years ago
Read 2 more answers
Henry has red marbles and blue marbles. The ratio of the number of his red marbles to blue marbles is 5:7 . If Henry has 63 blue
nika2105 [10]

Answer:

45 because 7 x 9 = 63 so you have to do 5 x 9 = 45

Step-by-step explanation:

8 0
3 years ago
Please give a good answer :)
Alex

Answer:

P(4≤x≤7) = 2/3

Step-by-step explanation:

We'll begin by obtaining the sample space (S) i.e possible outcome of rolling both dice at the same time. This is illustrated below:

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,2 6,3 6,4 6,5 6,6

Adding the outcome together, the sample space (S) becomes:

2 3 4 5 6 7

3 4 5 6 7 8

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

7 8 9 10 11 12

Next, we shall obtain the event of 4≤x≤7. This is illustrated below:

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

Finally, we shall determine P(4≤x≤7). This can be obtained as follow:

Element in the sample space, n(S) = 36

Element in 4≤x≤7, n(4≤x≤7) = 24

Probability of 4≤x≤7, P(4≤x≤7) = ?

P(4≤x≤7) = n(4≤x≤7) / nS

P(4≤x≤7) = 24/36

P(4≤x≤7) = 2/3

4 0
3 years ago
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