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Vitek1552 [10]
4 years ago
14

Tomas drew a rectangular with an area of 6 square centimeters. What is the greatest possible perimeter for this rectangle

Mathematics
1 answer:
anzhelika [568]4 years ago
8 0
There is no "greatest" possible perimeter.

There's a smallest possible perimeter.  That's a square.
Since the area is 6 square centimeters, each side of the square is
√6 = about 2.45 cm, and the perimeter is about  9.8 cm (rounded).

But there's no 'greatest' perimeter.  You can take that square
and if you're careful, you can make it into rectangles that all have
the same area ... 6 square cm ... but the longer and skinnier
you make it, the greater the perimeter will be. 
You can give me a number as big as you want, and I can make
a rectangle with a perimeter of your number, but an area of only
6 square centimeters !

Here are some few examples.  They all have
the same area, but different perimeters:

2.45 cm by 2.45 cm ...   Area = 6 square cm ... Perimeter = 9.8 cm

2 cm by 3 cm ...              Area = 6 square cm ... Perimeter = 10 cm
1.5 cm by 4 cm ...           Area = 6 square cm ... Perimeter = 11 cm
1.2 cm by 5 cm ...           Area = 6 square cm ... Perimeter = 12.4 cm
1 cm by 6 cm ...              Area = 6 square cm ... Perimeter = 14 cm
0.8 cm by 7.5 cm ...        Area = 6 square cm ... Perimeter = 16.6 cm
0.6 cm by 10 cm ...         Area = 6 square cm ... Perimeter = 21.2 cm
0.5 cm by 12 cm ...         Area = 6 square cm ... Perimeter = 25 cm
0.4 cm by 15 cm ...         Area = 6 square cm ... Perimeter = 30.8 cm
0.3 cm by 20 cm ...         Area = 6 square cm ... Perimeter = 40.6 cm
0.2 cm by 30 cm ...         Area = 6 square cm ... Perimeter = 60.4 cm
0.1 cm by 60 cm ...         Area = 6 square cm ... Perimeter = 120.2 cm

0.001cm by 6,000cm ... Area = 6 square cm ... Perimeter = 12,000.2 cm
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tino4ka555 [31]
Point E is the correct answer! :D
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4 years ago
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You borrow $5,000 from your parents to purchase a used car. The arrangements of the loan are such that you make payments of $250
AfilCa [17]
Part A:
1st month: Interest payable = 1% of $5,000 = $50.00
Amount paid in first month = $250 + $50.00 = $300
Unpaid balance = $5,000 - $250 = $4,750

2nd month: Interest payable = 1% of $4,750 = $47.50
Amount paid in second month = $250 + $47.50 = $297.50
Unpaid balance = $4,750 - $250 = $4,500

3rd month: Interest payable = 1% of $4,500 = $45.00
Amount paid in third month = $250 + $45.00 = $295.00
Unpaid balance = $4,500 - $250 = $4,250

4th month: Interest payable = 1% of $4,250 = $42.50
Amount paid in fouth month = $250 + $42.50 = $292.50
Unpaid balance = $4,250 - $250 = $4,000

5th month: Interest payable = 1% of $4,000 = $40.00
Amount paid in fifth month = $250 + $40.00 = $290.00
Unpaid balance = $4,000 - $250 = $3,750

6th month: Interest payable = 1% of $3,750 = $37.50
Amount paid in sixth month = $250 + $37.50 = $287.50
Unpaid balance = $3,750 - $250 = $3,500

7th month: Interest payable = 1% of $3,500 = $35.00
Amount paid in seventh month = $250 + $35.00 = $285.00
Unpaid balance = $3,500 - $250 = $3,250

8th month: Interest payable = 1% of $3,250 = $32.50
Amount paid in eighth month = $250 + $32.50 = $282.50
Unpaid balance = $3,250 - $250 = $3,000

9th month: Interest payable = 1% of $3,000 = $30.00
Amount paid in ninth month = $250 + $30.00 = $280.00
Unpaid balance = $3,000 - $250 = $2,750

10th month: Interest payable = 1% of $2,750 = $27.50
Amount paid in fouth month = $250 + $27.50 = $277.50
Unpaid balance = $2,750 - $250 = $2,500

11th month: Interest payable = 1% of $2,500 = $25.00
Amount paid in seventh month = $250 + $25.00 = $275.00
Unpaid balance = $2,500 - $250 = $2,250

12th month: Interest payable = 1% of $2,250 = $22.50
Amount paid in eighth month = $250 + $22.50 = $272.50
Unpaid balance = $2,250 - $250 = $2,000



Part B:
Number of payments = 5000 / 250 = 20
Total amount of interest = 50 + 47.5 + 45 + . . . + upto the 20th payment.
This is an arithmetic sequence with the first term as 50, common difference as -2.5 and number of terms = 20.

Sum of the first 20th term of the GP is given by
S_n= \frac{20}{2}[2(50)+(20-1)(-2.5)] \\  \\ =10(100-2.5(19))=10(100-47.5) \\  \\ =10(52.5)=\$525.00

Therefore, the <span>total amount of interest paid over the term of the loan is $525.00</span>
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3 years ago
Ryan is filling a box with 1-inch cubes. He filled the bottom layer as shown. Ryan wants to completely fill the box.
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Vsevolod [243]
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6 0
4 years ago
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What is the equation of the line that includes points (25, 100) and (15, 120)
julia-pushkina [17]

Answer:

y = -2x + 150

Step-by-step explanation:

y2 - y1 / x2 - x1

120 - 100 / 15 - 25

20 / -10

= -2

y = -2x + b

100 = -2(25) + b

100 = -50 + b

150 = b

3 0
3 years ago
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