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lianna [129]
3 years ago
13

23556 rounded to the nearest ten thousand

Mathematics
1 answer:
Vlada [557]3 years ago
5 0
20,000 is the answer! have a nice day.
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A biased coin has probability 0.6 of turning up heads. You win $x if a head comes up and you lose $y if a tail comes up. If your
Alexxandr [17]

Answer:

x,y will be in the ratio 2:3

Step-by-step explanation:

Given that a biased coin  has probability 0.6 of turning up heads

In other words, number of heads we obtain by tossing the coin would be binomial with p = 0.6 and q =1-p =0.4

If you toss one time, the distribution of U, no of heads would be

U    0     1

p   0.4   0.6

Winning amount would be 0.6x and losing amount would be 0.4y

If these two are equal then we have

0.6x=0.4y\\Or x:y = 2:3

3 0
3 years ago
Tell whether each graph shows a positive linear association, a negative association, a non-linear association, or no association
Paraphin [41]

Answer:

1-negative 2-non 3-positive 4-positve 5-non linear 6-negative



3 0
3 years ago
X2 + 4x -2 = -1<br>can someone solve this for me please<br>​
finlep [7]
I think this might be it. Hope it helps..

4 0
2 years ago
Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.
Ymorist [56]
See the attached figure
See the attached figure.
===================================
The first equation is 
4x + 2x²(3x-5) = 4x + 6x³ - 10x² = 6x³ - 10x² + 4x
So, The degree of the function = 3 , and the number of terms = 3
============================================================
The second equation is 
(-3x⁴ + 5x³ - 12 ) + ( 7x³ - x⁵ + 6 ) = -x⁵ -3x⁴ +12x³ - 6
So, The degree of the function = 5 , and the number of terms = 4
============================================================
The third equation is 
(3x² - 3)( 3x² + 3) = 9x⁴ - 9 
So, The degree of the function = 4 , and the number of terms = 2


7 0
3 years ago
Read 2 more answers
Help? Im lost with this one; someone tell me how
Alona [7]

Rationalizing the denominator of \frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }

we get \frac{\sqrt[3]{2} }{\sqrt[3]{z} }.

Option D is correct.

Step-by-step explanation:

We need to rationalize the denominator: \frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }

Solving:

\frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }

using Radical rule: \frac{\sqrt[n]{x}}{\sqrt[n]{y}}=\sqrt[n]{\frac{x}{y} }

=\sqrt[3]{\frac{2z}{z^2}}

=\sqrt[3]{\frac{2}{z^{2-1}}}

=\sqrt[3]{\frac{2}{z^{1}}}

=\sqrt[3]{\frac{2}{z}}

We can write it as:

\frac{\sqrt[3]{2} }{\sqrt[3]{z} }

So, rationalizing the denominator of \frac{\sqrt[3]{2z} }{\sqrt[3]{z^2} }

we get \frac{\sqrt[3]{2} }{\sqrt[3]{z} }.

Option D is correct.

Keywords: Radical Expression

Learn more about Radical Expression at:

  • brainly.com/question/7153188
  • brainly.com/question/10534381

#learnwithBrainly

8 0
4 years ago
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