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lianna [129]
3 years ago
13

23556 rounded to the nearest ten thousand

Mathematics
1 answer:
Vlada [557]3 years ago
5 0
20,000 is the answer! have a nice day.
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BRAINLIEST BRAINLIEST!!! <br> EASY MATH! Do with explanation!!
Anuta_ua [19.1K]

Answer:

<em>Answer is </em><em>given below with explanations</em><em>.</em><em>,</em>

Step-by-step explanation:

1)formula \: for \: linear \: equation \: is \:  \\ ax + by + c = 0 \\ 2) \: solution \: of \: the \: equation \: y = 9x - 3 \\ (2,15) \: is \: the \: solution \:  \\ on \: substitutuing \: the \: points \\ 15 = 9(2) - 3 \\ 15 = 18 - 3 \\ 15 = 15 \\ hence \: proved\\ 3) \: given \:( k,7) \: is \: a \: solution\\ \: of \: y =  - 4x + 1 \\ on \: substitutuing \: the \: points  \\ 7 =  - 4k + 1 \\ 4k =  - 7 + 1 \\ 4k =  - 6 \\ k = \frac{ - 6}{4}  \\ k = \frac{ - 2}{3}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>

3 0
3 years ago
How many significant digits are in thus number 74.30
goblinko [34]

Answer:

3

Step-by-step explanation:

all numbers except from zero

that would mean 7 4 and 3

so there would be 3 significant figures

I hope it goes well

7 0
3 years ago
A plot of grass behind a building is shown.
KATRIN_1 [288]

Answer:

62m

Step-by-step explanation:

16+16+8+12+10

=62m

3 0
3 years ago
Read 2 more answers
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
4 years ago
Three cube shaped boxes are stacked one above the other the volumes of two of the boxes are 1331 m³ each and the volume of the t
Pepsi [2]
So to find out the answer, you need to find out the dimensions of each cube. So for the 1331, it's 11 x 11 x 11. So you know that would be 11 meters high. Now the next cube. Then there's another 1331, so that would be another 11 meters high. Then 729, also 9 x 9 x 9, so that's going to be 9 meters high. Then add all the cube square roots. 11 + 11 + 9 = 31. So the height of the stacked boxes will be 31 meters.
5 0
3 years ago
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