Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Answer:
The first blank is m, the rest aren’t very clear
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Y-y1 = m(x-x1)
y-(-1) = 6 (x- -1)
answer: y = 6x-5
x(1.06)=5.25
The reason it is 1.06 is because it is the original cost plus tax. You can divide each side by 1.06 to get x roughly equals 4.95.
So $4.95 is roughly what the camera costs rounded to the nearest cent.