Question

Solve question 13. And 14. Please!! Will reward brainliest!!

Answer 1

Answer:

y = 4 sin( 0.5t - $\frac{4\pi }{3}$ ) - 2

y = a sin ( 2t - $\frac{-\pi }{3}$) + 2

Step-by-step explanation:

In the first question,

amplitude = 4

Period = $4\pi$

phase shift = $\frac{-4\pi }{3}$

Vertical shift = -2

Angular velocity , w = $\frac{2\pi }{time period}$

Here, w = $\frac{2\pi }{4\pi }$ = 0.5

The general equation of a wave is

y = a sin( wt + ∅ )

Putting above values in the equation,

y = 4 sin( 0.5t - $\frac{4\pi }{3}$ ) - 2

In the second question,

Amplitude is not given so we will take it as a.

time period = $\pi$

w = 2

Phase shift = $\frac{-\pi }{3}$

Vertical shift = 2

The equation is

y = a sin ( 2t - $\frac{-\pi }{3}$) + 2