(4,-16) factor 3/4
3/4 ×4=3 , -16×3/4= -12
B' (3,-12)
Answer:
The correct answer is the first solution set.
Step-by-step explanation:
If we substitute -20 into the equation we get
-20+17≤-3
-3≤-3
So,the inequality is right.
We can check the second one
14+17≤-3
31≤3 The inequality is false.
We can check the last one
-20+17≤-3
-3≤3 It works however there is a difference between the first one and the last one and that is the sign.For the first one there x≤-20 meaning the greatest number x can be is -20.For the last one x≥-20 which means -20 is the least value x can be.
If we substitude -21 into the equation we get
-21+17≤-3
-4≤-3
The inequality is false because -4 is not smaller than -3.
So,the right answer is the first solution set.
Answer:
w(w-5)
Step-by-step explanation:
Given Width of rectangle = w
Length of rectangle is 5 less than width of rectangle = w - 5
Area of Rectangle = Length x Width = w * w-5 = w(w-5)
Answer:
15 times 3 equals 60.
Step-by-step explanation:
9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
