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Sauron [17]
4 years ago
15

Jay collects eggs in a basket and weighs the basket. He graphed the relationship between the number of eggs

Physics
2 answers:
brilliants [131]4 years ago
7 0

Answer:

I don't really understand the numbers that you presented, but ill try to answer the question.

Jay is taking data on the weight of a basket with eggs depending on the number of eggs that is in the basket.

So for 1 egg, he knows that the basket weights w1

for 2 eggs he knows that the basket weights w2

and so on.

Then, in this context, if he does a linear relation of:

Weight = number of egs*k + b

where k is the slope and b is the y-intercept.

k represents the average weight of one egg, and b is the initial weight of the basket.

marissa [1.9K]4 years ago
4 0

Answer:

The answer is The mass per egg

Explanation:

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san4es73 [151]

Answer:

0.87 m

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Explanation:

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While no one knows why, astronomers do now know that the solar nebula has ___________?
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A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo
viva [34]

The fundamental frequency on a vibrating string is given by:

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

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Keeping this equation in mind, we can now answer the various parts of the question:

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In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor \sqrt{2}

In this case, the mass per unit length is doubled:

\mu'=2\mu

Substituting into the expression of the fundamental frequency, we find the new frequency:

f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}

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In this case, the tension is doubled:

T'=2T

Substituting into the expression of the fundamental frequency, we find the new frequency:

f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f

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8 0
3 years ago
Which of the following values represents an index of refraction of an actual material?
serg [7]

Sadly, we're forced to answer the question without the benefit of the
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Index of refraction of a substance =

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Any number greater than  ' 1 ' can be an index of refraction.  A number
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3 0
3 years ago
Why is it important that we learn about our solar system, the sun, and planets in our solar system other than Earth?
tangare [24]

Answer:

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8 0
3 years ago
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