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scoundrel [369]
2 years ago
14

Compare your response to the sample response above. what did your explanation include? the conclusion that the work was incorrec

t an explanation that talib did not switch the variables at the start an explanation that talib did not solve for the variable y
Mathematics
1 answer:
Alenkasestr [34]2 years ago
6 0

In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.

<h3>What is the variables  about?</h3>

Note that:

y=-8x+4

y-4=-8x

(y-4)/-8=x

Since the independent variable x is known, one can switch the variable labels and thus it will be:

y=(x-4)/-8

f^-1(x)=(x-4)/-8    

This can be written again as:

f^-1(x)=(4-x)/8  :P

Thus one can say  No, as he forgot to switch the variable labels after solving for the independent variable.

In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.

See the first part of the question below

Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your answer.

Learn more about variable from

brainly.com/question/4063302

#SPJ1

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Step-by-step explanation:

(2b-3)/(b-2)(b+2) = 3b(b-2)/(b+2)(b-2)

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5 0
3 years ago
Help me with the question of O.math​
Mashutka [201]

Answer:

24

Step-by-step explanation:

2*1+1+2*2+1+2*3+1+2*4+1=24

6 0
2 years ago
How do I factor trinomials of a form ax^2+bx+c when a=1 <br><br> In one paragraph
vitfil [10]

Answer:

  • Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

Step-by-step explanation:

As we know that a polynomial with three terms is said to be a trinomial.

Considering the trinomial of a form

ax^2+bx+c

As

a = 1

so

x^2+bx+c

  • Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

For example,

x^2+7x+10

=\left(x^2+2x\right)+\left(5x+10\right)

=x\left(x+2\right)+5\left(x+2\right)

\mathrm{Factor\:out\:common\:term\:}x+2

=\left(x+2\right)\left(x+5\right)

Therefore, Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

6 0
2 years ago
What is three fractions equivalent to 3/11
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3/11 *2 = 6/22
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3 0
3 years ago
If a student randomly guesses at 20 multiple-choice questions, find the probability that the student gets exactly four correct.
ad-work [718]

Answer:

Probability = 0.190

Step-by-step explanation:

Given:

Number of questions, 'n' = 20

Each question has four choices.

Let event of choosing correct answer be success and its probability be represented by 'p'.

Therefore, event of choosing wrong answer is failure and its probability be represented by 'q'.

Now, probability of success is choosing one correct answer out of 4 options. So, p=\frac{1}{4}=0.25

Now, 'p' and 'q' are complements of each other. Therefore,

q=1-p=1-0.25=0.75

Now, we need 4 successes. Therefore, x=4

Using Bernoulli's theorem to find 'x' successes from 'n' questions, we get:

P(x)=_{x}^{n}\textrm{C}p^xq^{n-x}

Plug in 4 for 'x', 20 for 'n', 0.25 for 'p' and 0.75 for 'q'. Solve.

P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{20-4}\\P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{16}\\P(4)=4845\times (0.25)^4\times (0.65)^{16}\\\\P(4)=0.1896\approx0.190

Therefore, the probability of getting 4 correct answers out of 20 questions is 0.190.

6 0
3 years ago
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