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3 years ago

Combine like terms.

Mathematics

2 answers:

coldgirl [10]3 years ago

8 0

Answer:

To solve the question the answer is 35y2 - 5 (i think)

Step-by-step explanation:

Yes and it's actually very simple.

To start off:

Simplify the equation: multiply 7 by the numbers in the parentheses getting: 28y2 - 35 .......full equation: 7y2 + (28y2 - 35)

New equation: 7y2 + (28y2 - 35) now combine like terms this means adding each common variable together. in this case, 7y2 and 28y2 would be added together to simplify the equation. Add them together, the new equation is: 35y2 - 5

Lmk if you have any questions i hope this helps

lutik1710 [3]3 years ago

6 0

Answer:

$7y^2+7\left(4y^2-5\right)=35y^2-35$

Step-by-step explanation:

Given the expression

$7y^2+7\left(4y^2-5\right)$

First Apply distributive law to expand 7(4y² - 5) : $a\left(b-c\right)=ab-ac$

$7y^2\:+7\left(4y^2\:-\:5\right)\:=7y^2+7\cdot \:\:\:4y^2-7\cdot \:\:\:5$

simplify

$=7y^2+28y^2-35$

Add like terms: 7y²+ 28y²=35y²

$=35y^2-35$

Therefore,

$7y^2+7\left(4y^2-5\right)=35y^2-35$

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3 years ago

Kathleen correctly determines four arithmetic means between −7 and 14. What values does Kathleen determine?

Annette [7]

Answer:

Kathleen determines the four arithmetic means to be −2.8 , 1.4, 5.6, and 9.8.

Step-by-step explanation:

The overall interval is 14 -(-7) = 21 units in length. The four equally-spaced "means" divide the interval into 5 equal parts, each one of which is ...

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3 years ago

Ted spent half of his weekly allowance playing arcade games. To earn more money his parents let him wash the car for $7. What is

GalinKa [24]

Answer:

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Step-by-step explanation:

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3 years ago

A sample of 47 observations is selected from a normal population. The sample mean is 30, and the population standard deviation i

erma4kov [3.2K]

Answer:

We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 29

Sample mean, $\bar{x}$ = 30

Sample size, n = 47

Alpha, α = 0.05

Population standard deviation, σ = 5

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 29\\H_A: \mu > 29$

a) This is a one-tailed test because the alternate hypothesis is in greater than direction.

We use One-tailed z test to perform this hypothesis.

b) $z_{stat} > z_{critical}$ , we reject the null hypothesis and accept the alternate hypothesis and if $z_{stat} < z_{critical}$ , we accept the null hypothesis and reject the alternate hypothesis.

c) Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{30 - 29}{\frac{5}{\sqrt{47}} } = 1.37$

d) Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} < z_{critical}$

We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

e) P-value is 0.0853

On the basis of p value we again accept the null hypothesis.

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3 years ago