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Vikki [24]
2 years ago
7

I don’t understand ..

Mathematics
2 answers:
svetoff [14.1K]2 years ago
8 0

Answer:

 1.791875241e13.

Step-by-step explanation:

The number of litres / year = 5.67811 * 10^5 * 3.15576 * 16^7

= 17.91875241 * 10^12

= 1.791875241* 10^13 or 1.791875241e13.

Nastasia [14]2 years ago
3 0

Answer:

Hey again, your answer would be:  1.79187524⋅1!!!

Hope this helps!

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Genrish500 [490]
Its 5/9 divide by five<span />
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A manager records the number of hours, X, each employee works on his or her shift and develops the probability distribution belo
Reika [66]

Answer:

c. 2

Step-by-step explanation:

Given : X = No. of hours worked

           No. of people work for the manager = 50

           X = 3, 4 , 5 , 6 , 7, 8

           P(X) = 0.1 , ? , 0.14 , 0.3 , 0.36 , 0.06

To Find : No. of people work for four hours

Solution : First understand the fact that sum of all probabilities is equal to 1

So, sum of all values of P(X) = 1

⇒0.1+?+0.14+0.3+0.36+0.06 = 1

⇒0.96+? = 1

⇒?= 1-0.96

⇒? = 0.04

So, the probability of no. of people worked for 4 hours is 0.04.

⇒P(4)=0.04

Thus , To calculate no. of people work for four hours :

0.04\times 50

⇒ 2 no. of people work for four hours per shift .


5 0
2 years ago
Read 2 more answers
Please help and thank you
zvonat [6]
The hexagonal prism has a an equation of volume = base * height.

Since we already know the base is 8 sq feet, we can plug in some values and use x as a missing value

40 = 8 * x
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5 = x

X is equal to 5.
7 0
2 years ago
a man is six times as old as his son in 9 years he will be three times as old as his son how old are they now
GuDViN [60]
The son is 4 years old and the dad is 24 years old.
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2 years ago
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the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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