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e-lub [12.9K]
3 years ago
14

Answer this right for a cookie

Mathematics
1 answer:
elena55 [62]3 years ago
6 0
Ouuuuuuuuuu I want a cookie
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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (39pt
WITCHER [35]

Angle O=64

Side m=7.3159882(rounded if needed)

Side n=16.68902(round if needed)

We are given

Angle M which equal 26.

Angle N equals 90 degrees

Side MN which equal 15.

We are asked to find all the missing elements of the triangle.

  1. Angle O can be found using triangle interior theorem so we can add 90+26+x =180 to find the value that satisfies the x value.

90 + 26 + x = 180

116 + x = 180

x = 64

Angle O=64 degrees

We can find side m by doing law of sines.

\frac{on}{ \sin(26) }  =  \frac{mn}{ \sin(64) }

\frac{on}{ \sin(26) }  =  \frac{15}{ \sin(64) }

on =  \frac{15}{ \sin(64) }  \times  \sin(26)

which is 7.315(round if neeeded).

We can find side n using pythagorean theorem,

{15}^{2}  +  {7.3}^{2}  =  {n}^{2}

225 + 53.29 =  {n}^{2}

\sqrt{278.29}

Side n=16.689(round if needed)

4 0
3 years ago
Olivia goes shopping at the mall and buys a shirt that is on sale for 25% off. She also knows that the sales tax is 5%. If her f
Norma-Jean [14]

Answer:   The shirt originally cost 125 dollars.

Step-by-step explanation: The shirt on sale is 25% off. So first multiply 25 by 5 and you get 125. So 125 is the originall price. Her final cost is 25 dollars. Last step: 125 divided by 5 equals 25 dollars.

3 0
3 years ago
For a certain population of men, 8 percent carry a certain genetic trait. For a certain population of women, 0.5 percent carry t
slavikrds [6]

Answer:

C) 150 men and 100 women

D) 200 men and 2000 women

E) 1000 men and 1000 women

Step-by-step explanation:

Hello!

To compare the proportion of people that carry certain genetic trait in men and woman from a certain population two variables of study where determined:

X₁: Number of men that carry the genetic trait.

X₁~Bi(n₁;p₁)

X₂: Number of women that carry the genetic trait.

X₂~Bi(n₂;p₂)

The parameter of interest is the difference between the population proportion of men that carry the genetic trait and the population proportion of women that carry the genetic trait, symbolically: p₁-p₂

To be able to study the difference between the population proportions you have to apply the Central Limit Theorem to approximate the distribution of both sample proportions to normal.

<u><em>Reminder:</em></u>

Be a variable with binomial distribution X~Bi(n;p), if a sample of size n is taken from the population in the study. Then the distribution of the sample proportion tends to the normal distribution with mean p and variance (pq)/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

So for both populations in the study, the sample sizes should be

n₁ ≥ 30

n₂ ≥ 30

Also:

Both samples should be independent and include at least 10 successes and 10 failures.

Both populations should be at least 20 times bigger than the samples. (This last condition is to be assumed because without prior information about the populations is impossible to verify)

  • If everything checks out then (p'₁-p'₂)≈N(p₁-p₂; p(1/n₁+1/n₂))

<u>The options are:</u>

A) 30 men and 30 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 30*0.08= 2.4

Failures: y₁= n₁*q₁= 30*0.92= 27.6

Population 2

Successes: x₂= n₂*p₂= 30*0.5= 15

Failures: y₂= n₂*q₂= 30*0.5= 15

The second condition is not met.

B) 125 men and 20 women

n₁ ≥ 30 but n₂ < 30

Both samples are independent but n₂ is not big enough for the approximation.

C) 150 men and 100 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 150*0.08= 12

Failures: y₁= n₁*q₁= 150*0.92= 138

Population 2

Successes: x₂= n₂*p₂= 100*0.5= 50

Failures: y₂= n₂*q₂= 100*0.5= 50

All conditions are met, an approximation to normal is valid.

D) 200 men and 2000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 200*0.08= 16

Failures: y₁= n₁*q₁= 200*0.92= 184

Population 2

Successes: x₂= n₂*p₂= 2000*0.5= 1000

Failures: y₂= n₂*q₂= 2000*0.5= 1000

All conditions are met, an approximation to normal is valid.

E) 1000 men and 1000 women

n₁ ≥ 30 and n₂ ≥ 30

Both samples are big enough and independent.

Population 1

Successes: x₁= n₁*p₁= 1000*0.08= 80

Failures: y₁= n₁*q₁= 1000*0.92= 920

Population 2

Successes: x₂= n₂*p₂= 1000*0.5= 500

Failures: y₂= n₂*q₂= 1000*0.5= 500

All conditions are met, an approximation to normal is valid.

I hope this helps!

6 0
3 years ago
The isosceles triangle has a perimeter of 7.5 m. Which equation can be used to find the value of x if the shortest side, y, meas
kicyunya [14]
An isosceles triangle has 2 sides of the same length and one side that's not the same length.

So it says the shortest side, y, is 2.1m, so that means it's the side that is not the same length as the other two sides.

But the other two sides will be the same length. Let's make those 2 sides x.

The equation would be
x + x + 2.1 = 7.5

And with that you can find x.
3 0
3 years ago
Read 2 more answers
What is e+3/8=2 answer
kvasek [131]

Answer:

1\frac{5}{8}

or

1.6

6 0
3 years ago
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