12. For which of the following solids are all cross sections circular?

What is the answer to (5x20)-6

Zina [86]

Answer:

the awnser is 94 because 5×20=100-6=96

3 0

3 years ago

2. - 4x + 9y = 14 12x – 10y = -8 ; multiplication

NeTakaya

Answer:

Step-by-step explanation: (Equation 2) = 12(-12+9y/4) - 10y = -8

-144+108y/4 - 10y = -8

-144 + 108y - 40y/4 = -8

-144 + 108y - 40y = -32

108y - 40y = -32+144

68y = 112

Y= 1.64

2-4x+9y=14

12x-10y= -8

2-14+9y = 4x

-12 + 9y = 4x ( equation 3)

(Put in equation 2)

3 0

3 years ago

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Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

$\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}$

$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

$\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}$

$\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}$

$\mathsf{\implies \dfrac{5 - 1}{5 + 1}}$

$\mathsf{\implies \dfrac{4}{6}}$

$\mathsf{\implies \dfrac{2}{3}}$

Hence, option (a) 2/3 is your correct answer.

3 0

3 years ago

Simplify the following

Goshia [24]

Answer:

9

Step-by-step explanation:

Using the rules of logarithms

log $x^{n}$ = nlogx

$log_{b}$ b = 1

Then

$log_{x}$ $x^{9}$

= 9 $log_{x}$ x

= 9

4 0

3 years ago

6w-19 + k when w=8 and k = 2

ddd [48]

Answer:

31.

Step-by-step explanation:

1. Write out the problem.

6w-19 + k; w=8 and k=2

2. Figure out the first part of the problem.

So, if w=8 and 6 and w are next to each other, we should multiply 6*8, which is 48. Next, it says to subtract 19. 48-19=29.

3. Find out what the last part of the problem is.

Since the first part of the problem is 29 and k=2, we should add 29+2=31, which is the final answer.

Hope this helped :)

3 0

4 years ago

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