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Maksim231197 [3]

3 years ago

5

Suppose you find that the correlation coefficient for a set of data is 0.826. What is the coefficient of determination and what

does it mean?

1 answer:

Vladimir [108]3 years ago

6 0

Answer:

$r^2 = 0.826^ 2 =.6822$

$r^2 =$ a measure of how strong the ("how fit") the relationship is

it is always positive between 0 and 1

Step-by-step explanation:

coefficient of determination = r^2

r^2 = 0.826^ 2 =.6822

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#3 Can someone please help me with these questions!!!!

rosijanka [135]

Answer:

Option A 90,68

$m\angle 1=90^o$

$m\angle 2=68^o$

Step-by-step explanation:

see the attached figure to better understand the problem

The figure shows a kite

we know that

A kite properties include

1) two pairs of consecutive, congruent sides

2) congruent non-vertex angles

3) perpendicular diagonals

Find the measure of angle 1

we have that

$m\angle 1=90^o$ ----> by the diagonals are perpendicular

Find the measure of angle 2

we know that

triangle AEB is congruent with triangle CEB

so

$m\angle EAB=m\angle ECB=m\angle 2$

In the right triangle EAB

$m\angle EAB+22^o=90^o$ ----> by complementary angles in a right triangle

so

$m\angle EAB=90^o-22^o=68^o$

therefore

$m\angle 2=68^o$

7 0

3 years ago

Can someone please help? I’m not very good with cubes. Thanks!

goblinko [34]

Answer:

green with yellow

orange with purple

blue with brown

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The length of a rectangle is (x + 1) cm and its width is 5cm less than its length.

NeX [460]

Answer:

a) the area of a square is in terms of x is

$(x+1)^2$ centimeter square

b)The length of the rectangle is l = (x+1)

l = 7+1 =8 cm

The width of the rectangle is w = [(x+1)-5]

w = (7+1)-5 =3 cm

Step-by-step explanation:

a) the area of a square is in terms of x is

area of square is $l^{2} = (x+1)(x+1)$

= $(x+1)^2$

b) Given length is l = (x+1) cm and

the width is 5 cm less than its length.

so we have take width is w = (x+1)-5 cm

Given area of triangle is 24 cm

Area of rectangle = length X width

24 = (x+1)(x+1 -5 )

now simplification $24 = (x+1)^2 - 5 (x+1)$

apply (a+b)^2 = a^2+2 a b+b^2

$x^2+2 x+1-5 x-5 =24$

$x^2 -3 x -4-24=0$

$x^{2} -3 x -28 =0$

now find factors of 28 = 7 X 4 is

$x^{2} -7 x+4 x-28=0$

$x(x-7)+4(x-7)=0$

$(x+4)(x-7)=0$

x = -4 and x=7

there fore you have to choose x = 7

The length of the rectangle is l = (x+1)

l = 7+1 =8

The width of the rectangle is w = [(x+1)-5]

w = (7+1)-5 = 3

<u>Verification:-</u>

Given area of rectangle = 24 = 8 X 3

24 =24

so we can not choose x=-4

we have to choose x =7 only

7 0

3 years ago

Given that D(x) = 2x, select all of the following that are true statements

Keith_Richards [23]

Answer:

D(x) is a function

D(x) is a direct variation

D(x) is a rule for the set of points (5.10). (6, 12) and (-2,-4)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem

$D(x)=2x$

D(x) is a direct variation (linear function)

The variable x is the independent variable or input value

The variable D(x) is the dependent variable or output value

<u><em>Verify each statement</em></u>

case 1) D(x) is a function

The statement is true

see the explanation

case 2) x is the dependent variable

The statement is false

The variable x is the independent variable or input value

case 3) D(x) is a direct variation

The statement is true

see the explanation

case 4) D(x) is a rule for the set of points (5.10). (6, 12) and (-2,-4)

The statement is true

Because

For x=5

substitute in the linear equation

$D(x)=2(5)=10$ ---> is ok

For x=6

substitute in the linear equation

$D(x)=2(6)=12$ ---> is ok

For x=-2

substitute in the linear equation

$D(x)=2(-2)=-4$ ---> is ok

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3 years ago

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Ngl idk but just be a nice person and mark as brainliest please

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3 years ago