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3 years ago

How many real does this 2x^2-5x+3=0 equation have

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

3 0

2 $x^{2}$ -5x+3=0

x= $\frac{-(-5)+ \sqrt{(-5) ^{2}-4*2*3 } }{2*2}$

x=3/2;x=1

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What is the ratio of 2 cups of water for 1 cup of rice

alexdok [17]

Answer:

2 to 1; 2:1

Step-by-step explanation:

There are two cups of water and one cup of rice. It's a two to one ratio.

5 0

4 years ago

Read 2 more answers

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0

3 years ago

Find the seventh term of the geometric sequence 1, 2, 4, ... and the sum of the first seven terms. t7= S7=

IrinaK [193]

Answer:

Seventh term is 64

Sum of the first seven terms is 127

Step-by-step explanation:

The common ratio is 2

$a_{n} = a_{1} r^{n - 1}$

n = 7 and the first term is 1. So,

$a_{7} = 1(2^{7 - 1} ) = 2^{6} = 64$

Seventh term is 64

$S_{n} = \frac{a_{1} (r^{n} -1)}{r - 1}$

$S_{7} = \frac{1(2^{7} -1)}{2 - 1}$

$= \frac{128 - 1}{1} = 127$

Sum of the first seven terms is 127

8 0

3 years ago

What is one point that lies in the solution set of the

Vlad [161]

Substitute the given point (3, -2) in each condition
(i) y < -3; y ≤ (2/3)x - 4
-2 < -3 → False
Therefore, it is not a solution.
[Since the values of x and y must satisfy both the conditions, if one of them does not satisfy the condition then it is not necessary to check the other one.]
(ii) y > -3; y ≥ 2/3x - 4
-2 > -3 → True
y ≥ 2/3x - 4
-2 ≥ -2 → True
Therefore, it is a solution.
(iii) y < -3; y ≥ 2/3x - 4
-2 < -3 → False
Therefore, it is not a solution.
(iv) y > -2; y ≤ 2/3x - 4
-2 > -2 → False
Therefore, it is not a solution.
Thereofore, the system of linear inequalities having the point (3, -2) in its solution set is y > -3; y ≥ 2/3x - 4. Hope it helps you.

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3 years ago

Scrie numarul 13421 ca: a.suma de doua numere naturale; b.diferenta de doua numere naturale;

krek1111 [17]

13421= 10000+3421 (sumã de două nr. naturale)
13421= 23000-9579 (diferența de 2 nr. naturale)

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3 years ago