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damaskus [11]
4 years ago
5

Write the equation for k(x) k(x) = 3x + 6

Mathematics
1 answer:
Travka [436]4 years ago
5 0
K-1(x) = 1/3x - 2

You can get this by switching the x and k(x) and then solve for the new k(x)
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Use the following diagram to find the angle measures of the triangle, rounded to the nearest degree.
nadezda [96]

Answer:

m∠A = 30°

m∠B = 80°

m∠C = 70°

Step-by-step explanation:

By applying cosine rule in the given triangle,

b² = a² + c² - 2ac[cos(∠B)]

From the given triangle,

a = 14 m

b = 28 m

c = 24 m

(28)² = (14)² + (24)² - 2(14)(24)cos(B)

784 = 196 + 576 - 672cos(∠B)

cos(∠B) = 0.1786

∠B = \text{cos}^{-1}(0.1786)

∠B = 79.71°

∠B = 80°

By applying sine rule in the given triangle,

\frac{\text{sinA}}{a}= \frac{\text{sinB}}{b}= \frac{\text{sinC}}{c}

\frac{\text{sinA}}{14}= \frac{\text{sin(79.71)}}{28}= \frac{\text{sinC}}{24}

\frac{\text{sinA}}{14}= \frac{\text{sin(79.71)}}{28}

\text{sinA}= \frac{\text{sin(79.71)}\times 14}{28}

sinA = 0.491958

A = 29.47°

A ≈ 30°

By applying triangle sum theorem,

m∠A + m∠B + m∠C = 180°

30° + 80° + m∠C = 180°

m∠C = 70°

4 0
3 years ago
What is the difference between Laplace Transform and fourier Transform?
marta [7]

Real time mapping of a function to a new function is known as Fourier transforms. The new mapped function is defined for an interval of (-∞, ∞).

<span>While the Laplace transform is the counterpart, in which a function is mapped to a new function on complex plane. Functions defined for span t≥0 are used by Laplace transformation. </span>

5 0
3 years ago
-3 1/6 divide by (-2 1/3)
marshall27 [118]

Answer:

1 5/14

Step-by-step explanation:

-3 1/6 / -2 1/3

-3 1/6 = -19/6

-2 1/3 = -7/3

-19/6 / -7/3 = -19/6 x -3/7

-19 x -3 = 57

-6 x -7 = 42

57/42 = 1 5/14

6 0
3 years ago
Pls help meeee!<br> and show work and explain so I can understand better.
olchik [2.2K]

Answer:

806 meters

Step-by-step explanation:

3 0
3 years ago
Simply the imaginary number square root -45
Paraphin [41]

Answer:

3i\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

and \sqrt{-1} = i

Given

\sqrt{-45}

= \sqrt{9(5)(-1)}

= \sqrt{9} × \sqrt{5} × \sqrt{-1}

= 3 × \sqrt{5} × i

= 3i\sqrt{5}

6 0
3 years ago
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