All categories

3 years ago

Please help ASAP! what is x=-b/2a?

Mathematics

1 answer:

valina [46]3 years ago

5 0

This is the formula to solve for the vertex.

Example Question:

Find the vertex of y = -0.5x^2 + 100x

-b/2a = -100/2(-0.5) = -100/-1 = 100

The x coordinate of the vertex is 100.

Best of Luck!

P.S. this is 1000th question i've answered :)

You might be interested in

Herman and Jackie are saving money to pay for college. Herman currently has $15,000 and is working hard to save $1000 per month.

Mashutka [201]

Answer:

Part 1) $10\ months$

Part 2) $\$25,000$

Step-by-step explanation:

Let

y ----> the total amount of savings

x ----> the number of months

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

Herman

The slope is equal to $m=\$1,000\ per\ month$

The y-intercept is $b=\$15,000$

substitute

$y=1,000x+15,000$ ----> equation A

Jackie

The slope is equal to $m=\$1,300\ per\ month$

The y-intercept is $b=\$12,000$

substitute

$y=1,300x+12,000$ ----> equation B

Part 1) In how many months will they have the same amount of savings?

equate equation A and equation B

$1,300x+12,000=1,000x+15,000$

solve for x

$1,300x-1,000x=15,000-12,000$

$300x=3,000$

$x=10\ months$

Part 2) How much will each of them have saved?

substitute the value of x=10 months in any of the equations

equation A

$y=1,000(10)+15,000=\$25,000$

equation B

$y=1,300(10)+12,000=\$25,000$

7 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

NeX [460]

Answer:

(a) 0.343

(b) 0.657

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

$p = \frac{70}{100} = 0.7$

Let P(a vehicle not passing the test) = q

q = 1 - p

q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

= 0.7 × 0.7 × 0.7

= 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

= (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

= 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

= 0.657

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.063 + 0.063 + 0.063

= 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

= 0.063 + 0.063 + 0.063 + 0.027

= 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

= (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

= 0.973

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

$= \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}$

$= \frac{0.343}{0.973}$

= 0.353

3 0

3 years ago

Read 2 more answers

I don't understand no this at all

Katena32 [7]

Answer:

Just get the perimeter of the smaller rectangle then times it by 4

Step-by-step explanation:

i tried to use a calculator but i cant do the perimeter of the smaller triangle because i dont know what x is sorry ill try to figure it out.

8 0

3 years ago

A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to

Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

$P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916$

B) Here X is Bin (8, 0.1)

$P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488$

C) Here X is Bin (20,5)

$P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319$

3 0

3 years ago

What is the value of the larger zero of the function: f(x) = 3x^2– 14x + 15?

AVprozaik [17]

Answer:

Step-by-step explanation:

can you plz tell me what this is is it a multiplt??

4 0

3 years ago