What is the arc length of an angle of 7π 6 radians formed on the unit circle?

1 answer:

4 0

Well you know that the formula for arc length is S = θr where θ is the radian measure of intersection and r is the radius. So, $S = \frac{7 \pi }{6} * 1$
S = $\frac{7 \pi }{6}$

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Kobotan [32]

Answer:

Step-by-step explanation:

You use the quadratic equation and substitute these values from the equation given

a=1,b=5, c=2

Which gives you the value of option A

6 0

3 years ago

Let p: A number is greater than 25.

maria [59]

We are given that:
p is greater than 25, this means that p>25
p ∈ ]25,∞[ ...........> interval I

q is less than 35, this means that q<35
q ∈ ]-∞,35[ ...........> interval II

The given condition p ∧ q is true means that (p and q) is true. In other word, their intersection is true.
Therefore, the final result would be the intersection between the two intervals (interval I and interval II)

Bases on the above, the final answer would be:
]-∞,35[ ∧ ]25,∞[ which is ]25,35[

8 0

3 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Ierofanga [76]

The area of the triangle is $2\sqrt{3}$ = 3.4641 square feet.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.

In the given triangle, the hypotenuse is the side that is represented by c. The other sides on the triangle are represented by the values a and b.

Step 2:

Assume the other side of the triangle measures x units.

So according to the Pythagorean theorem,

$4^{2} = (2\sqrt{3} )^{2} + x^{2} , x^{2} = 4^{2} - (2\sqrt{3} )^{2} .$