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kherson [118]
2 years ago
9

Zoe takes out a $5,155 loan at a rate of

Mathematics
1 answer:
Irina-Kira [14]2 years ago
6 0

Answer:

5,888.67

Step-by-step explanation:

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Simplify the expression below 3x+2 -3x+7 +5x
spin [16.1K]
6x + 9

First, simplify x

3x + -3x + 5x = 6x

Then, simplify the rest of the numbers:

2 + 7 = 9

Then make the equation:

6x + 9
5 0
2 years ago
What is Question I (if m<EBF = 117°, fine m<ABE)​
Natasha_Volkova [10]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* Lets look to the figure to solve the problem

- AC is a line

- Ray BF intersects the line AC at B

- Ray BF ⊥ line AC

∴ ∠ABF and ∠CBF are right angles

∴ m∠ABF = m∠CBF = 90°

- Rays BE and BD intersect the line AC at B

∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure

∴ BE is the bisector of angle ABD

∵ m∠EBF = 117°

∵ m∠EBF = m∠ABE + m∠ABF

∵ m∠ABF = 90°

∴ 117° = m∠ABE + 90°

- Subtract 90 from both sides

∴ m∠ABE = 27°

4 0
3 years ago
Read 2 more answers
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
2 years ago
A rectangle has a perimeter 204 it’s length six feet longer than twice it’s width if L stands for the rectangle and W stands for
andriy [413]

Answer:

W=32

L=70

Step-by-step explanation:

L=2w+6

204=2L+2W

204=2w+2(2w+6)

204=2w+4w+12

192=6w

w=32

L=2(32)+6

L=70

6 0
2 years ago
Geometry help needed!
lilavasa [31]

Answer:

13.76

Step-by-step explanation:

Area of the whole

The area of the whole = s^2 (the firgure is a square

s = 8

Area of the whole = 8^2 = 64

Area of the unshaded part

The 2 half circles = 1 whole circle

The radius of the 1/2 circle = 4 (eight has been cut in half)

Area of two half circles = 2* (pi r^2/2)

Area of two half circles = 2 * (pi 4^2/2)

area of two half circles =  16*pi

Area of the shaded area

Area of the shaded area = area of the whole - area of the unshaded area

Area of the shaded area = 64 - 16*pi

Area of the shaded area = 64 - 3.14*16 = 13.76

4 0
3 years ago
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