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2 years ago

What is the area of the large circle?

Mathematics

2 answers:

Andru [333]2 years ago

3 0

Answer:

7.07 or 7.06858

Step-by-step explanation:

I used the google area of a circle calculator

jarptica [38.1K]2 years ago

3 0

To find the area of a circle just do pi*r^2

So basically

1.5*1.5*3.14

And you get 7.06500

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Citrus2011 [14]

First answer is the correct answer

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2 years ago

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How to put percent into decimal

fiasKO [112]

Answer:

There are multiple ways to do so:

You can divide the number by 100 to convert it to a decimal

You could take your percentage and add a decimal two places to the left.

Examples of both:

For division its as simple as 75 divided by 100 = 0.75

If we are going to use the decimal method, lets say we have 45%, so we can do this:

45% =45.00

Move the decimal two places to the left.

0.45

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2 years ago

Round 0.868 to the nearest tenth.

Anna11 [10]

Answer: 0.9

Step-by-step explanation:

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2 years ago

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A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$

Now we have everything in order to replace into formula (1):

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

5 0

3 years ago

P(t) = 250 * (3.04)^t/1.98,

Alex17521 [72]

Answer:

The concept which best describes the change of the population is the derivative of $p(t)=250(3.04)^{\frac{t}{1.98}}$ .

Step-by-step explanation:

Observe that the function $p(t)=250(3.04)^{\frac{t}{1.98}}$ describes the amount of rabbits at the time t (in years) but no the rate of change of the population at a given instant. So you have to use the derivative of $p(t)$ to obtain that rate of change at any instant. For example, if we derivate the function $p(t)=250(3.04)^{\frac{t}{1.98}}$ we obtain:

$p'(t)=250\cdot \log(\frac{1}{1.98})(3.04)^{\frac{t}{1.98}}$

And if we want to find the rate of change at $t=5$ years we evaluate

$p'(5)=250\cdot \log(\frac{1}{1.98})(3.04)^{\frac{5}{1.98}}=2326$ rabbits/year

5 0

3 years ago