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Tema [17]
3 years ago
11

The solution to the given system of linear equations lies in which quadrant? 1, 2, 3, or 4

Mathematics
2 answers:
Alchen [17]3 years ago
8 0
Lies on the 4th quadrant

Aneli [31]3 years ago
8 0

Answer:

The correct option is 4. The solution of given system of equation is (3,-1), which lies in 4th quadrant.

Step-by-step explanation:

The given equations are

x-3y=6                  .... (1)

x+y=2                   .... (2)

Subtract equation (2) from equation (1).

x-3y-(x+y)=6-2

x-3y-x-y=4

-4y=4

Divide both sides by -4.

y=-1

The value of y is -1.

Substitute y=-1 in equation (1).

x-3(-1)=6

x+3=6

Subtract 3 from both sides.

x=6-3

x=3

The solution of given system of equation is (3,-1).

Since the x coordinate is positive and y coordinate is negative, therefore the solution of given system of equation lies in 4th quadrant.

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What is 6920 divided by 4
7nadin3 [17]

ANSWER

ITS ANSWER IS 1730

6 0
3 years ago
Read 2 more answers
1. Find an algebraic representation for an exponential function if it is known that f(x + 1) = 4.f(x)
MrMuchimi

f(x)=4^{x-1} is the algebraic representation for an exponential function

Step-by-step explanation:

Given:

f(x + 1) = 4.f(x)

f(3) = 16

To Find:

Algebraic representation for an exponential function=?

Solution:

From the formula f(x+n) = 4^n f(x)

when n= 1, x= 3

f(3+1)= 4(1)f(3)

f(4)= 4f(3)

Substituting the value of f(3)

f(4)= 4f(3)

f(4)= 4 x 16  

f(4)= 64

f(4)=4^2

f (5) = 4^2 x 16

f (5) = 4^2 x  4^2

f(5)= 4^4

Similarly,

F(6) = 4^5

Hence, f(x)=4^{x-1}

4 0
3 years ago
What is the distance between two points on the globe 30° north and 50° south​
wlad13 [49]

Answer:

The distance between two points on the globe 30° north and 50° south at the equator is the same as latitude, roughly 69 miles. At 45 degrees north or south, the distance between is about 49 miles (79 km). The distance between longitudes reaches zero at the poles as the lines of meridian converge at that point.

Step-by-step explanation:

Sorry If it is wrong.

3 0
3 years ago
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
How do I solve y = a + 151
bulgar [2K]

Answer:I don’t know I’m in sixth grade

Step-by-step explanation:

6 0
3 years ago
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