Which side of the mountain faces

tigry1 [53]

The water dissolves the salt because the water molecules are able to interact with the salt-forming particles, called ions. When the water Interacts with the trainers of the salt ions, the solid salt crystal structure Suffers breakdown, until the trainers of the salt ions are completely surrounded by water molecules. At this time the salt is fully dissolved by water.

hope this helps!

4 0

2 years ago

Which scientists is credited with developing the firdt scientific atomic theory

ratelena [41]

<em>Answer: </em>John Dalton

Explanation: Democritus was a Greek philosopher (470-380 B.C.) who is the father of modern atomic thought. He proposed that matter could NOT be divided into smaller pieces forever. John Dalton created the very first atomic theory.

5 0

2 years ago

When reading any volume in the laboratory, we always read where the bottom of the water curve falls. This is called the______?

zavuch27 [327]

Answer: Meniscus

Explanation: There is a condition on reading volumes. For concave meniscus read volume in the lower part and for convex meniscus read volume at the upper part.

7 0

2 years ago

Read 2 more answers

Which statement correctly describes the Ka of a weak acid?

katovenus [111]

The answer is D) <span>The Ka is small, and the equilibrium favors reactants.

</span>

6 0

3 years ago

Read 2 more answers

On a hot summer day you and some friends decide you want to cool down your pool. Determine the mass of ice you would need to add

sergeinik [125]

Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is $16.14 \times 10^{4}$ kg.

Explanation:

We know that relation between heat energy and specific heat is as follows.

q = $m \times S \times \Delta T$

As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.

Mass of water = Volume × Density

= $400,000 L \times 1 kg/L$

= 400,000 kg

or, = $400,000 \times 10^{3}$ g (as 1 kg = 1000 g)

Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.

$\Delta T$ = 305 K - 273 K

= 32 K

Now, putting the given values into the above formula and calculate the heat energy as follows.

q = $m \times S \times \Delta T$

= $400,000 \times 10^{3} \times 4.2 \times 32 K$

= $5376 \times 10^{7}$ J

or, = $5376 \times 10^{4}$ kJ

According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of $5376 \times 10^{4}$ kJ is calculated as follows.

Mass = $\frac{5376 \times 10^{4} kJ}{333 kJ/Kg} \times 1 kg$

= $16.14 \times 10^{4}$ kg

Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is $16.14 \times 10^{4}$ kg.

3 0

2 years ago