Answer:

Explanation:
Hello,
For the given chemical reaction:

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

Finally, we compute the percent yield with the obtained 2.10 g:

Best regards.
Answer:
Total Ionic equation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
Explanation:
Chemical equation:
H₂O₂(aq) + MgSO₃(aq) → MgSO₄(aq) + H₂O(l)
Balanced chemical equation:
H₂O₂(aq) + MgSO₃(aq) → MgSO₄(aq) + H₂O(l)
Total Ionic equation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
Water can not split into ions because it is present is liquid form.
The answer is acidity, because pH indicators help indicate the H+ or OH- concentration in a solution. H+ concentrations create acids, and OH- make bases. pH indicators don’t indicate any of the other answers in the question, so the answer is Acidity.
Answer:
They have properties of both metals and nonmetals
Explanation:
- Elements in the periodic table may be divided into Metals, non-metals, and metalloids.
- Metals are the elements that react by losing electrons to form stable positively charged ions known as cations. Examples are group 1, 2, and 3 elements together with transition elements.
- Non-metals are those elements that react by gaining electrons to form stable negatively charged ions called anions. Examples include oxygen, carbon, sulfur, etc.
- Metalloids, on the other hand, are elements that have both metallic and non-metallic properties.
- Metalloids occur between metals and non-metals in the periodic table. Examples include Boron and silicon among others.
Answer:
B. 4-methylhex-1-ene
Explanation:
There are 6 carbons for the main molecule of 1-hexene. They are counted from the first (1) on the terminal C with the double bond (ene). A methyl group is hanging on carbon number 4, so it is the 4-methyl.
4-methylhex-1-ene.