The number of chlorine atoms present on the product side of the reaction is 6
<h3>What is a chemical equation? </h3>
Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
<h3>How to determine the number of atoms of Cl</h3>
2Al + 6HCl → 2AlCl₃ + 3H₂
Products => AlCl₃ and H₂
Number of Cl atoms = 2 × 3
Number of Cl atoms = 6 atoms
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First of all the ethylamine is base so will be react with water to take the proton from the water (H⁺) , because water is amphoteric will react with bases as acid and acids as a base, so the water in this case will react as an acid and will gives the proton to the base.
In the picture you may see the chemical equation and the structure of the products.
Answer:
V₂ ≈416.7 mL
Explanation:
This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.
where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.
The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,
- V₁= 600 mL
- T₁= 360 K
- T₂= 250 K
Substitute the values into the formula.
- 600 mL /360 K = V₂ / 250 K
Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.
- 250 K * 600 mL /360 K = V₂ / 250 K * 250 K
- 250 K * 600 mL/360 K = V₂
The units of Kelvin cancel, so we are left with the units of mL.
- 250 * 600 mL/360=V₂
- 416.666666667 mL= V₂
Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.
The volume of the balloon at 250 K is approximately 416.7 milliliters.
Answer:
MgO + 2HBr → MgBr2 + H2O
Explanation:
I actually couldn't guess at first what the question is. But looking closely at the statements, I deduced that some are correct and some are not. So, I think this is a true or false problem. So,
<span>The 1s orbital(s) do(es) not have any nodes. - This is false. Nodes are the planes that the orbitals do not fill. The formula for the number of nodes is:
N = n - l
where
n is the energy level
l is 0 for s subshell, 1 for p subshell, 2 for d subshell, 3 for f subshell; l also signifies the number of angular nodes.
Thus,
N = 1 - 0 = 1 node
</span><span>The 1s orbital(s) has(have) a node at the nucleus. Since this is the opposite of the first statement, this is true.
</span><span>The 3d orbital(s) has(have) a cloverleaf shape, with four lobes of electron density around the nucleus and two perpendicular nodal planes.
This is true. The shape of d subshell is cloverleaf, and all have four lobes. Since l=2, there are 2 perpendicular or angular nodes.
</span><span>The f orbitals are even more complex. This is true. The f subshell is the last subshell. It has complex shapes and it rarely comes up in chemistry.
</span><span><em>The number of nodes (and nodal planes) depends on the specific orbital, but there will be more than for s, p, or d orbitals. </em><em />This is false. In fact, f orbitals have more nodes because l = 3. That means they always have 3 angular nodes, which is greater than the other subshells.</span>
