The age of a man whose normal blood pressure measures 123 mm of hg
9 years
<h3>What is Quadratic equation ?</h3>
A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = a
+ bx + c, where a, b, and c are numbers and a cannot be 0
P(A) = 0.006 
- 0.02a + 120
123 = 0.006- 0.02a + 120
0=0.006 - 0.02a - 3
you can use the quadratic equation formula to solve for the man's age.
A = (-b ± (
) ) / (2a)
A = (0.02 ± 
/ (2*0.006)
A = (0.02 ± 
) / 0.012
A = 9 , -5.67
Age of the man will be 9 years
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Answer:
6000 cm<em>²</em>
Explanation:
let width of rectangle = 
Using Pythagorean theorem,
+<em> 50² = 130²</em>
<em /><em> = 130² - 50² </em>
<em /><em> = 14400</em>
<em /> <em>= 120 cm</em>
area of rectangle <em>=</em> length x width
<em>=</em> <em>120 x 50</em>
<em>= 6000 cm²</em>
On isolated ground receptacles, the metal yoke is not allowed to be integrally bonded to the equipment grounding terminal of the receptacle.
Any device with two distinct switches or receptacles is a duplex device. It can be shaped to fit a Decora opening or a typical duplex plate opening. It should be noted that they can be combination devices with a switch/outlet, switch/pilot light, etc.
Because of grounding connection removal and receptacle, it is utterly undesirable to connect the two bare equipment grounding conductors together directly.
The equipment grounding conductor associated with those circuits must be connected to the box when circuit conductors are terminated on equipment inside a metal box to prevent unneeded current discharge.
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Answer:
(d) III only
Explanation:
We have to observe the motion of the bag with respect to taxi , considering taxi as stationary or inertial frame . Since bag is not moving with respect to taxi , the inertial frame that means , net force on it is zero .So option i and ii are ruled out .
Now how to explain motion of the bag ie why it is stationary ie what are the balancing force acting on it. We know that on a body on circular path , a force called centripetal force is acting on it . So that force must be acting on it . The balancing force is the frictional force which is keeping it stationary with respect to taxi . Hence the third option is correct.
Answer:
191.36 N/m
Explanation:
From the question,
The Potential Energy of the safe = Energy of the spring when it was compressed.
mgh = 1/2ke²............... Equation 1
Where m = mass of the safe, g = acceleration due to gravity, h = height of the save above the heavy duty spring , k = spring constant, e = compression
Making k the subject of the equation,
k =2mgh/e²................ Equation 2
Given: m = 1100 kg, h = 2.4 mm = 0.0024 m, e = 0.52 m
Constant: g = 9.8 m/s²
Substitute into equation 2
k = 2(1100)(9.8)(0.0024)/0.52²
k = 51.744/0.2704
k = 191.36 N/m
Hence the spring constant of the heavy-duty spring = 191.36 N/m
