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dlinn [17]
3 years ago
10

Which situations contain unbalanced forces? Check all that apply.

Physics
2 answers:
coldgirl [10]3 years ago
8 0

A book falls to the floor.

A car skids to a stop.

A foam ball launches from a spring (Are the right answer, just did this one 4:34 pm Jan/21/19)

Triss [41]3 years ago
7 0

Answer:

B. A book falls to the floor.

C. A car skids to a stop.

F. A foam ball launches from a spring

Hope this helps

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Please help me with this question ASAP.
victus00 [196]

Answer:

i. 6.923 V

ii. The e.m.f. = 22.5 V

Explanation:

i. The given parameters are;

Length of potentiometer = 1 m

The resistance of the potentiometer = 10 Ω

The e. m. f. of the attached cell = 9 V

The current, I flowing in the circuit = e. m. f/(Total resistance)

The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A

The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire

The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V

ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;

\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}

Where:

E = e.m.f. of the balance point cell

R_{balance} = Resistance of 75 cm of potentiometer wire  = 0.75×10 = 7.5 Ω

R_{cell} = Resistance of the cell in the circuit = 3 Ω

V = e.m.f. attached cell = 9 V

\dfrac{E}{7.5} = \dfrac{9}{3}

E = 7.5*3 = 22.5 V

The e.m.f. = 22.5 V

7 0
4 years ago
For a brass alloy, the stress at which plastic deformation begins is 345 MPa (50,000 psi), and the modulus of elasticity is 103
Alona [7]

Answer:

a) P = 44850 N

b) \delta l =0.254\ mm

Explanation:

Given:

Cross-section area of the specimen, A = 130 mm² = 0.00013 m²

stress, σ = 345 MPa = 345 × 10⁶ Pa

Modulus of elasticity, E = 103 GPa = 103 × 10⁹ Pa

Initial length, L = 76 mm = 0.076 m

a) The stress is given as:

\sigma=\frac{\textup{Load}}{\textup{Area}}

on substituting the values, we get

345\times10^6=\frac{\textup{Load}}{0.00013}

or

Load, P = 44850 N

Hence<u> the maximum load that can be applied is 44850 N = 44.85 KN</u>

b)The deformation (\delta l) due to an axial load is given as:

\delta l =\frac{PL}{AE}

on substituting the values, we get

\delta l =\frac{44850\times0.076}{0.00013\times103\times 10^9}

or

\delta l =0.254\ mm

3 0
3 years ago
A 10 kg gun recoils with a speed of 0.1 m/s after it fires a 0.001 kg bullet. What is the speed of the bullet?
Kitty [74]

As we know that here gun + bullet system is isolated from all other external force system

so here the momentum of system is always conserved

so we will say

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

v_{1i} = v_{2i} = 0

m_1 = 10 kg

m_2 = 0.001kg

v_{1f} = 0.1 m/s

now we will have

0 + 0 = 10(0.1) + 0.001v_{2f}

by solving above equation we will have

v_{2f} = 1000 m/s

3 0
3 years ago
Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds. approximately how far
Ivahew [28]

Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds,  approximately  Vega will be 25.076 Light year or 7.692 Parsec away from the sun

The parallax angle is the angle between the Earth at one time of year, and the Earth six months later, as measured from a nearby star.

Mathematically it can be understood as that the parallax angle is the angle which is taken from a point at one time on the earth and again after six months later from the same point on the earth. The parallax angle is the semi-angle of inclination between the two lines to sight.

Stellar parallax is the basis for the parsec, which is the distance from the Sun to an astronomical object that has a parallax angle of one arcsecond.

Distance (in parsec) = 1 / (parallax angle ( arcsec))

given

parallax angle = 0.13 arcseconds

Distance (in parsec) = 1/ 0.13 = 7.692 Parsec

if 1 Parsec = 3.26 Light year

So, 7.692 Parsec will be equal to =  3.26 * 7.692 = 25.076 Light year

                                                        ≈ 25.076 Light year

To learn more about Stellar parallax here

brainly.com/question/4885471?referrer=searchResults

#SPJ4

5 0
2 years ago
Which of the following describes the relationship between work and power?
Vinvika [58]

Answer: The answer is B

Explanation:

Work can be defined as the energy that is required to apply a force to an object in order to move it from one point to another. In physics, work = force x distance travelled. On the other hand, Power is the work done per time. In other words, it the rate at which work is done and is determined by using the formula, Power = Work/time. In these relationships, it can be seen that power is directly proportional to the amount of work done, hence as power increases, more work is done.

6 0
3 years ago
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