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ValentinkaMS [17]
3 years ago
5

xFormula1" title=" \frac{5x}{x + 4} + \frac{x - 6}{x + 4} " alt=" \frac{5x}{x + 4} + \frac{x - 6}{x + 4} " align="absmiddle" class="latex-formula">
idk this ;-; btw this is addition of rational algebraic expressions
​
Mathematics
2 answers:
Ne4ueva [31]3 years ago
4 0
The Answer is 100% 38
laiz [17]3 years ago
3 0
The answer of this question will be 38
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A lidless box is to be made using 2m^2 of cardboard find the dimensions of the box that requires the least amount of cardboard
Jlenok [28]
1.8, Problem 37: A lidless cardboard box is to be made with a volume of 4 m3 . Find the dimensions of the box that requires the least amount of cardboard. Solution: If the dimensions of our box are x, y, and z, then we’re seeking to minimize A(x, y, z) = xy + 2xz + 2yz subject to the constraint that xyz = 4. Our first step is to make the first function a function of just 2 variables. From xyz = 4, we see z = 4/xy, and if we substitute this into A(x, y, z), we obtain a new function A(x, y) = xy + 8/y + 8/x. Since we’re optimizing something, we want to calculate the critical points, which occur when Ax = Ay = 0 or either Ax or Ay is undefined. If Ax or Ay is undefined, then x = 0 or y = 0, which means xyz = 4 can’t hold. So, we calculate when Ax = 0 = Ay. Ax = y − 8/x2 = 0 and Ay = x − 8/y2 = 0. From these, we obtain x 2y = 8 = xy2 . This forces x = y = 2, which forces z = 1. Calculating second derivatives and applying the second derivative test, we see that (x, y) = (2, 2) is a local minimum for A(x, y). To show it’s an absolute minimum, first notice that A(x, y) is defined for all choices of x and y that are positive (if x and y are arbitrarily large, you can still make z REALLY small so that xyz = 4 still). Therefore, the domain is NOT a closed and bounded region (it’s neither closed nor bounded), so you can’t apply the Extreme Value Theorem. However, you can salvage something: observe what happens to A(x, y) as x → 0, as y → 0, as x → ∞, and y → ∞. In each of these cases, at least one of the variables must go to ∞, meaning that A(x, y) goes to ∞. Thus, moving away from (2, 2) forces A(x, y) to increase, and so (2, 2) is an absolute minimum for A(x, y).
5 0
4 years ago
The first figure is dilated to form the second figure.
ladessa [460]
The scale factor is 2.5
6 0
3 years ago
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Which value of X is a solution of x&lt;-2<br><br> A.-3<br> B.-2<br> C.-1<br> D.0
iren [92.7K]

Answer:

A.) -3

Step-by-step explanation:

-3 is less than -2 therefore, it fits the answer.

8 0
3 years ago
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What is the exact volume of the cone?
victus00 [196]
Answer:  [D]:  " 196π  in.³  "  .
_____________________________________________________
Explanation:
_____________________________________________________
Given: radius, "r", equal 7 in.
Given: height, "h", equals 4 in.

Volume:  V = Base area * h ; 

The base area of a cone is a circle:  A = π * r²  = π* (7²) = 49π .

(NOTE: Since all answer choices given are in terms of "π" ; we will leave the units in terms of "π").

V = (Based area) * h = (49π  in.) * (4 in.) = (49*4)π  in.³
   =  196π  in.³  ; which is: Answer choice: [D] .
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8 0
4 years ago
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What figure appears to be the image of figure h after a dilation by a scale factor of 1/2 and a rotation of 180 degrees?
Fofino [41]

Answer:

Figure D

Step-by-step explanation:

we know that

If the scale factor of the dilation is 1/2, that means the dilation is a reduction

so

the answer is between the Figure C and Figure D

but  

a rotation of 180° eliminate the Figure C

therefore

The answer is the Figure D

6 0
3 years ago
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