You stand at point C and look at an aquarium tank. Calculate the radius of the aquarium tank.
2 answers:
Answer:
8.25
Step-by-step explanation:
DC = 14ft
AC = 8ft + the diametre
Lets use d for diametre
The equation we are using is the Segments of Secants and Tangents Theorem, which is = 8ft (or the outside segment) * AC (the whole segment)
= 8 * (8 + d)
196 = 64 + 8d
Subtract 64 from 196 to get: 132 = 8d
Divide 8 from 132 to get: d = 16.5
Now the diametre is 16.5, but the radius is half the diametre, so now you have to do: 16.5 / 2
So the radius would end up being 8.25
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Answer:
F is E reflected across the y-axis; only the signs of the x-coordinates of F and E are different.
Step-by-step explanation:
The question is incomplete. Here is the complete question.
" Points F and E on the coordinate grid below show the positions of two midfield players of a soccer team:
Coordinate grid shown from negative 4 to positive 4 on x-axis and negative 4 to positive 4 on y-axis. From the origin, point E is 1.5 units to the left and 3 units up. From the origin, point F is 1.5 units to the right and 3 units up.
Which statement best describes the relationship between the positions of the two midfield players? (1 point)
Based on the coordinate of E;
The value on the x axis is -1.5 since the point is 1.5unitsTO THE LEFT from the origin(-ve x-axis acts towards the left in space). The value on the y-axis will be +3units since its 3units UP(+ve y axis acts upward).
The E coordinates will therefore be (-1.5, 3)
Similarly, for coordinate F:
If from the origin, point F is 1.5 units TO THE RIGHT, then the x-axis will be +1.5 (x-axis is positive towards the right) and +3 units up(+ve y axis acts upward).
The F coordinate will therefore be;
(1.5, 3).
From both coordinates, it can be seen that both x axis are of the same value but different signs. This means that the points E and F will act in the opposite side of the y-axis and a reflector of each other.
Based on the explanation above, it can be concluded that "F is E reflected across the y-axis; only the signs of the x-coordinates of F and E are different."
