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coldgirl [10]
3 years ago
14

You stand at point C and look at an aquarium tank. Calculate the radius of the aquarium tank.

Mathematics
2 answers:
Levart [38]3 years ago
7 0

Answer:

8.25

Step-by-step explanation:

DC = 14ft

AC = 8ft + the diametre

Lets use d for diametre

The equation we are using is the Segments of Secants and Tangents Theorem, which is DC^{2} = 8ft (or the outside segment) * AC (the whole segment)

14^{2} = 8 * (8 + d)

196 = 64 + 8d

Subtract 64 from 196 to get: 132 = 8d

Divide 8 from 132 to get: d = 16.5

Now the diametre is 16.5, but the radius is half the diametre, so now you have to do: 16.5 / 2

So the radius would end up being 8.25

leonid [27]3 years ago
3 0

Answer:

The radius of the aquarium tank is 8.25\ ft

Step-by-step explanation:

we know that

Applying the Tangent Secant Theorem

DC^{2}=AC*8

we have that

AC=(D+8)\ ft

DC=14\ ft

substitute

14^{2}=(D+8)*8

196=8D+64

Solve for D

8D=196-64

8D=132

D=16.5\ ft

Find the radius

The radius is half the diameter

r=16.5/2=8.25\ ft

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Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3
polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256

#learnwithBrainly

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